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A-LevelChemistryElectrochemistry9701/42 · Feb/Mar 2021 · Q18 Marks

The most common oxidation states of cobalt are +2 and +3. Complete the electronic configurations of the following free ions. • Co2+ [Ar] • Co³+ [Ar]

  1. (a)The most common oxidation states of cobalt are +2 and +3. Complete the electronic configurations of the following free ions. • Co2+ [Ar] • Co³+ [Ar][1]
  2. (b)Co2+ and Co³+ both form complexes with edta⁴-. half-equation E°/V Co3+ + e- ⇌ Co2+ +1.82 O2 + 4H+ + 4e¯ ⇌ 2H₂O +1.23 [Co(edta)] + e¯ ⇌ [Co(edta)]2- +0.38 Co2+ + 2e- ⇌ Co -0.28 Use the data in the table to predict what happens, if anything, when separate aqueous solutions of Co³+ and [Co(edta)] are left to stand in the air. aqueous solution of Co³+ aqueous solution of [Co(edta)]-[3]
  3. (c)Hydrated cobalt(II) nitrate, Co(NO3)2•6H2O, is a red solid that behaves like hydrated magnesium nitrate, Mg(NO3)2•6H₂O, when heated. Describe in detail what you would expect to observe when crystals of Co(NO3)2•6H2O are heated in a boiling tube, gently at first and then more strongly.[2]
  4. (d)Explain why the thermal stability of the Group 2 nitrates increases down the group.[2]

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Mark scheme

Marking points from the official mark scheme (Feb/Mar 2021). The mark or mark type is shown in brackets.

  1. [1] Co2+ = [Ar] 3d7 (4s°); Co3+ = [Ar] 3d6 (4s°)
  2. [3] M1/2: (for Co3+ solution) Co3+ is reduced to Co2+; oxygen gas/O2 is evolved; E of Co3+ greater than E of O2 (any two for 2 marks)
  3. [3] M3: (for [Co(edta)]- solution) no change (to [Co(edta)]¯) / not feasible OWTTE
  4. [2] condensation on tube / steam evolved; brown fumes / brown gas evolved; O2 formed that relights a glowing splint; (solid) dissolves / turns to liquid (any two visual observations)
  5. [2] M1: cationic radius / ion size increases (down the group)
  6. [2] M2: less polarisation / distortion of nitrate ion / anion / NO3-

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About this question

Topic
Electrochemistry, A-Level Chemistry (syllabus 9701). Structured question, 8 marks.
Source
A-Level Chemistry, Feb/Mar 2021 Paper 4 Variant 2, question 1.

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