Compound F has been found in small quantities in some cereals and dried fruit. [Figure 4.1]
- (a)(i)Give the name of the functional groups labelled A and B. A B[2]
- (a)(ii)State the number of chiral carbon atoms in one molecule of F.[1]
- (b)F can be hydrolysed by heating with an excess of dilute hydrochloric acid, as shown. Three products are formed: G and two others. [Figure 4.2] Draw the structures of the other products of the reaction in the boxes provided.[3]
- (c)(i)State the role of FeCl₃ in this step.[1]
- (c)(ii)Use the Data Booklet to suggest two reasons why the chlorine atom in compound H substitutes into the ring at the position shown, instead of the other positions in the ring. 1 2[2]
- (d)(i)Calculate the number of carbon atoms, x, present in J. x =[2]
- (d)(ii)The mass spectrum has a peak at m/e = 205. Suggest the identity of the fragment lost from J to form this peak.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2020). The mark or mark type is shown in brackets.
- [2] A = ester
- B = (2°) amide
- [1] 2
- [3] M1 phenylalanine
- M2 protonated amine
- M3 (ethanol) CH3CH2OH
- [1] catalyst / halogen carrier
- [2] M1 -OH directs to 2,4 AND both 2 positions occupied / only position 4 is available
- M2 -COOH directs to 3 position AND only position 3 is available / 5 is occupied
- [1] x = 14.4/100 × 100/1.1 = 13.1
- 13 carbon atoms (some working required)
- [1] (250 - 205 = 45, so) CO2H / C2H5O
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