Hydrated zinc sulfate has the formula ZnSO4•yH2O where y is an integer. Hydrated zinc sulfate decomposes when heated, losing only its water of crystallisation and becoming anhydrous. You will determine the value of y in ZnSO4•yH2O by heating the hydrated salt until it becomes anhydrous. FA 4 is hydrated zinc sulfate, ZnSO4•yH2O.
- (a)Method • Weigh the crucible with its lid. Record the mass in the space for Results. • Add between 3.20 g and 3.40 g of FA 4 to the crucible. • Weigh the crucible with its lid and FA 4. Record the mass. • Place the crucible on the pipeclay triangle. Gently heat the crucible and contents for approximately 2 minutes with the lid on. • Remove the lid. Heat the crucible and contents strongly for approximately 4 minutes. • Replace the lid and leave the crucible and residue to cool for at least 5 minutes. You may wish to begin work on Question 3 while the crucible is cooling. • Weigh the crucible with its lid and its contents. Record the mass. • Remove the lid. Heat the crucible strongly for approximately 3 minutes. • Replace the lid and leave the crucible and residue to cool for at least 5 minutes. • Weigh the crucible with its lid and its contents. Record the mass. • Calculate the mass of FA 4 used and the mass of residue obtained. Record the masses. Results[5]
- (b)(i)Calculations Calculate the amount, in mol, of anhydrous zinc sulfate residue formed in the decomposition of FA 4. Calculate the amount, in mol, of water of crystallisation lost. amount of ZnSO4 = ................................... mol amount of H2O = ................................... mol [2][2]
- (b)(ii)Calculate the value of y in the formula ZnSO4•yH2O. Show your working. y = ................................... [2][2]
- (c)A student suggests using this thermal decomposition method to investigate the number of moles of water of crystallisation in hydrated ethanedioic acid. The teacher says that this method is unsuitable. Suggest why this method is unsuitable. [1][1]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2025). The mark or mark type is shown in brackets.
- [1] I Six correct headings with units in results space • (Mass) crucible + lid / g • (Mass) crucible + lid + FA 4 / g • (Mass) crucible + lid + residue / contents after first heating / g • (Mass) crucible + lid + residue after second heating / g • (Mass) FA 4 (used) / g • (Mass) residue / g Display of units: / g, (g), in g, in gram(me)s or in (column) heading covering all entries
- [1] II Four readings in space provided • All four weighings recorded to same decimal places (either to two or to three) • Reading after 2nd heating within + 0.02 and – 0.05 of reading after 1st heating
- [1] III Correct subtractions • Correct calculations of mass FA 4 and residue AND • Mass of FA 4 is between 2.90 and 3.40 g.
- [2] IV and V Accuracy Theoretical value = 1.78 Calculate and record candidate's mass ratio = mass FA 4 / mass of residue. Award IV if 1.51 < candidate's mass ratio < 2.05 Award V if 1.60 < candidates mass ratio < 1.96
- [1] Correctly uses M1 Amount ZnSO4 = mass residue / 161.5 mol AND answer given to 2 – 4 sf
- [1] Correctly calculates M2 Amount H2O = mass water lost / 18 mol AND answer given to 2–4 sf
- [1] M1 y = moles H2O / moles ZnSO4
- [1] M2 Expression evaluated and y correctly calculated quoted as integer
- [1] The (anhydrous ethanedioic) acid would decompose (on heating) / is flammable
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