Fig. 6.1 shows two reactions of ethanedioic acid, HOOCCOOH. [Figure 6.1]

1. (a)(i)Draw the organic product G in the box in Fig. 6.1.[1]
2. (a)(ii)In Fig. 6.1, SOCl₂ is given as the reagent that reacts with HOOCCOOH to produce G. Identify a different reagent that also reacts with HOOCCOOH to produce G.[1]
3. (b)Identify two different reagents that oxidise HOOCCOOH to form carbon dioxide and water.[2]
4. (c)HOOCCOOH ionises as shown. HOOCCOOH ⇌ HOOCCOO⁻ + H⁺ HOOCCOOH is a much stronger acid than methanoic acid, HCOOH. Suggest an explanation for this difference in acidity.[2]
5. (d)(i)Benzene-1,4-dicarboxylic acid, HOOCC₆H₄COOH, can be made from benzene, C₆H₆, in two steps as shown in Fig. 6.2. [Figure 6.2] Suggest the identity of J by drawing its structure in the box in Fig. 6.2.[1]
6. (d)(ii)Identify the reagents and conditions for step 1 and step 2. step 1 step 2[2]
7. (d)(iii)Draw the structure of exactly one repeat unit of the polymer formed when benzene-1,4-dicarboxylic acid reacts with ethane-1,2-diol, HOCH₂CH₂OH. The linkage formed between the monomers should be shown fully displayed.[2]
8. (d)(iv)State the type of polymerisation that occurs when benzene-1,4-dicarboxylic acid reacts with ethane-1,2-diol and name the linkage formed between the monomers. type of polymerisation linkage[1]

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