Fig. 2.1 shows an incomplete energy cycle. [Figure 2.1]
- (a)Predict and explain the variation in enthalpy change of hydration for the ions Na⁺, Mg²⁺ and Al³⁺.[3]
- (b)(i)Complete line C on Fig. 2.1. Include state symbols.[1]
- (b)(ii)Use both words and symbols to identify change 2 on Fig. 2.1. Use changes 1 and 3 as examples of how this should be done.[2]
- (b)(iii)Calculate a value for the lattice energy of magnesium chloride, ΔHlatt MgCl₂(s), by selecting and using appropriate data from Table 2.1. Table 2.1 energy change value/kJ mol⁻¹ enthalpy change of solution of magnesium chloride -155 enthalpy change of formation of magnesium chloride -642 first ionisation energy of magnesium +736 second ionisation energy of magnesium +1450 electron affinity of chlorine -349 enthalpy change of hydration of Mg²⁺ -1920 enthalpy change of hydration of Cl⁻ -364 ∆Hlatt MgCl₂(s) = kJ mol⁻¹[3]
- (c)Define entropy.[1]
- (d)At 25°C the enthalpy change of solution of compound Z is +26kJmol⁻¹. The entropy change of solution of Z at the same temperature is +52JK⁻¹mol⁻¹. Calculate the value of the Gibbs free energy change, ΔG, for the solution of Z at 25 °C. ΔG = kJ mol⁻¹[2]
- (e)(i)Use your answer to (d) to predict whether or not Z is soluble in water at 25°C. Explain your answer.[1]
- (e)(ii)Predict whether Z becomes more or less soluble as the water is heated from 25°C to 95°C. Explain your answer.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [1] ΔHhyd increases from left to right due to increase in charge
- [1] ionic radius decreases from left to right
- [1] causing increased attractive force to water molecules
- [1] Mg²⁺ (aq) + 2Cl⁻ (aq)
- [1] Enthalpy change of hydration of magnesium ions and chloride ions
- [1] ΔHhydMg²⁺ + 2ΔHhydCl⁻
- [1] Selects 155, 1920 and 364 only
- [1] 2 x 364
- [1] answer -2493
- [1] The number of arrangements of the particles and of the energy in the system
- [1] ΔG = ΔH – TΔS
- [1] answer +10.5
- [1] No, ΔG is positive
- [1] Becomes more / soluble because ΔG becomes more negative / less positive / smaller / closer to zero
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