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A-LevelChemistryAtomic structure9701/22 · Oct/Nov 2024 · Q19 Marks

Vanadium, niobium and tantalum are metals in the same group of the Periodic Table.

  1. (a)The shorthand electronic configuration of vanadium in the ground state is [Ar]3d³4s².
  2. (a)(i)State what is meant by the term ground state.[1]
  3. (a)(ii)Show the electronic configuration of vanadium using electrons in boxes notation. [Ar] ____ ____ ____ ____ ____[1]
  4. (a)(iii)Deduce the total number of electrons in the p sub-shells of a vanadium atom.[1]
  5. (b)Pelopium was the suggested name for a new element discovered in a mineral. Pelopium was later found to be a mixture of niobium, Nb, and tantalum, Ta. Only one naturally occurring isotope exists for each of Nb and Ta.
  6. (b)(i)Complete Table 1.1. Table 1.1 | isotope | relative isotopic mass | number of protons | number of neutrons | |---|---|---|---| | ⁹³₄₁Nb | 92.91 | | | | ¹⁸¹₇₃Ta | 180.95 | | |[2]
  7. (b)(ii)Define relative isotopic mass.[2]
  8. (b)(iii)A sample of pelopium contains 90.9% by mass ⁹³₄₁Nb and 9.1% by mass ¹⁸¹₇₃Ta. Calculate the theoretical relative atomic mass of pelopium based on these data and Table 1.1. Give your answer to two decimal places. Show your working. theoretical relative atomic mass of pelopium = [2]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.

  1. [1] lowest energy state owtte examples • (with) lowest energy • (with) no external energy • (with) no added energy • (where) electrons are not promoted to a higher energy level most energetically stable
  2. [1] [Ar] ↑ ↑ ↑ The 3 x d electrons may go in any of the d orbitals
  3. [1] 12
  4. [2] isotope | RIM | # protons | # neutrons ---|---|---|--- ⁹³₄₁Nb | 92.91 | • 41 | • 52 ¹⁸¹₇₃Ta | 180.95 | • 73 | • 108
  5. [1] M1 mass of an (atom of an) isotope [1] M2 relative/compared to (the mass of) the unified atomic mass unit OR on a scale in which a carbon-12 atom / isotope has a mass of exactly 12 units OR divided by / compared to 1/12 of the mass of a carbon-12 atom / isotope Alternative route using mass of 1 mol throughout M1 mass of one mol of an (atom of an) isotope M2 relative/compared to 1/12 of the mass of 1 mol of C-12 atom / isotope OR when the mass of one mol C-12 atom / isotope is exactly 12(.000) g
  6. [1] 92.91× 0.909 + 180.95 × 0.091
  7. [1] = 100.92

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About this question

Topic
Atomic structure, A-Level Chemistry (syllabus 9701). Structured question, 9 marks.
Source
A-Level Chemistry, Oct/Nov 2024 Paper 2 Variant 2, question 1.

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