The elements phosphorus, sulfur and chlorine are in Period 3 of the Periodic Table. Table 1.1 shows some properties of the elements P to Cl. The first ionisation energy of S is not shown. Table 1.1 property P S Cl number of electrons in 3p subshell total number of unpaired electrons first ionisation energy /kJ mol⁻¹ 1060 1260 formula of most common anion P³⁻ S²⁻ Cl⁻
- (a)(i)Complete Table 1.1 to show the number of electrons in the 3p subshell and the total number of unpaired electrons in an atom of P, S and Cl.[2]
- (a)(ii)Construct an equation to represent the first ionisation energy of P.[1]
- (a)(iii)Three possible values for the first ionisation energy of S are given. 1000 kJ mol⁻¹ 1160 kJ mol⁻¹ 1320 kJ mol⁻¹ Circle the correct value. Explain your choice by comparing your chosen value to those of P and Cl.[4]
- (b)(i)Give the full electronic configuration of P³⁻.[1]
- (b)(ii)State the trend in ionic radius shown by P³⁻, S²⁻ and Cl⁻. Explain your answer.[2]
- (c)A student does three tests on separate samples of NaCl(aq). Complete Table 1.2 with the observations the student makes in each test. Table 1.2 test observations 1 addition of a few drops of Br₂(aq) 2 addition of a few drops of concentrated H₂SO₄ 3 addition of a few drops of dilute AgNO₃(aq)[3]
- (d)(i)Explain how the information in (d) suggests the structure and bonding of POCL₃ is simple covalent.[2]
- (d)(ii)Construct an equation for the reaction of POCL₃ with water. POCL₃ + →[1]
- (d)(iii)POCL₃ contains a double covalent bond between P and O. Complete the dot-and-cross diagram, in [Figure 1.1], to show the bonding in POCL₃. Show outer shell electrons only.[2]
- (e)(i)Define enthalpy change of formation, ΔHᶠ.[2]
- (e)(ii)Calculate the bond energy of P=O in POCl₃ using the data in Table 1.3. Show your working.[2]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.
- [1] total # 3p e- 3 4 5
- [1] total # unpaired e- 3 2 1
- [1] P(g) → P⁺(g) + e(-)
- [1] 1000 (kJmol⁻¹)
- [1] (S) less / least/lowest nuclear attraction (to outer electrons) (than P OR Cl) OR nuclear attraction for Cl is stronger (compared to S (and or P))
- [1] S less nuclear charge than Cl OR Cl has a greater nuclear charge than S
- [1] (S has a greater nuclear charge (of outer electrons) than P BUT) S has two electrons in a (3)p orbital AND resulting in spin-pair repulsion
- [1] 1s² 2s² 2p⁶ 3s² 3p⁶
- [2] • decreases (from P³⁻ to Cl⁻) • increased attraction (of outer e⁻) for nucleus owtte • increased nuclear charge • same shielding
- [1] (Br₂) no visible reaction OR colourless to orange / brown / yellow solution
- [1] (conc. H₂SO₄) no visible reaction OR Solution remains colourless
- [1] (dil. AgNO₃) white precipitate forms
- [1] (relatively low melting and boiling points suggests) weak intermolecular / VdW forces
- [1] (vigorous reaction with water suggests) hydrolysis
- [1] POCl₃ + 3H₂O → H₃PO₄ + 3HCl
- [1] Correct bonding e-
- [1] rest of electrons correct (i.e. to make 32 electrons in total)
- [1] enthalpy change when one mole of a compound / substance is formed
- [1] from its constituent elements in their standard states
- [1] 2(-592) = 2(−289) + (496) – 2(P=O) OR (2) P=O = 2(−289) + (496) + 2(592)
- [1] Ep=O = ½(1102) = +551 (kJ mol⁻¹)
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