Benzene, C₆H₆, is an aromatic molecule.
- (a)State the C–C–C bond angle and the hybridisation shown by the carbon atoms in benzene. bond angle hybridisation[1]
- (b)(i)Benzene reacts with chloroethane in the presence of a catalyst. The reaction mechanism is called electrophilic substitution. The first step in the reaction is the generation of the ⁺CH₂CH₃ electrophile. Write an equation for the reaction that generates this electrophile.[1]
- (b)(ii)Describe the mechanism for the reaction between benzene and the ⁺CH₂CH₃ electrophile. Include all relevant curly arrows and charges. [Figure with benzene and electrophile to complete intermediate and products][3]
- (c)(i)Chlorobenzene and chloroethane have different reactivities in nucleophilic substitution reactions. Identify a suitable reagent to illustrate this difference in reactivity. The reagent chosen should give visibly different results with chlorobenzene and chloroethane.[1]
- (c)(ii)Write equations to describe any reactions that occur.[1]
- (c)(iii)Explain the difference in the reactivities of chlorobenzene and chloroethane in nucleophilic substitution reactions.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2022). The mark or mark type is shown in brackets.
- [1] 120° AND sp²
- [1] C₂H₅Cl + AlCl₃ → CH₃CH₂⁺ + AlCl₄⁻
- [3] curly arrow 1 AND curly arrow 2 [1] correct intermediate structure [1] C₆H₅C₂H₅ AND H⁺ [1]
- [1] (aqueous / alkaline) AgNO₃ / silver nitrate
- [1] C₂H₅Cl + H₂O → C₂H₅OH + HCl / C₂H₅Cl + NaOH → C₂H₅OH + NaCl AND Ag⁺ + Cl⁻ → AgCl AND NO equation shown for C₆H₅Cl
- [1] lone pair / p-orbital from Cl overlaps with benzene ring AND stronger / partial double C-Cl bond OR difficult to break C-Cl bond
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