Compound T is made by a three-stage synthesis. [Figure showing a synthesis pathway: phenylethanoic acid -> (stage 1) Compound R (C₆H₅CH₂COCl) -> (stage 2) Compound S (C₆H₅CH₂CONHCH₂CH₃) -> (stage 3) Compound T]
- (a)In stage 1, phenylethanoic acid reacts with a suitable reagent to form compound R. [Figure showing phenylethanoic acid reacting to form R] Suggest a suitable reagent for stage 1.[1]
- (b)(i)In stage 2, compound R reacts with ethylamine to form compound S. [Figure showing R reacting with C₂H₅NH₂ to form S] Name the functional group formed in stage 2.[1]
- (b)(ii)Identify the other product formed in stage 2.[1]
- (c)(i)In stage 3, compound S reacts with a suitable reagent to form compound T. [Figure showing S reacting to form T] State the formula of a suitable reagent for stage 3.[1]
- (c)(ii)Name the type of reaction that occurs in stage 3.[1]
- (d)(i)The relative abundance of the molecular ion peak in the mass spectrum of ethylamine is 62. Calculate the relative abundance of the M+1 peak in the mass spectrum of ethylamine.[1]
- (d)(ii)The mass spectrum of compound T contains several fragments. The m/e values of two of these fragments are 29 and 91. Draw the structures of the ions responsible for these peaks.[2]
- (e)(i)The proton (¹H) NMR spectrum of compound T shows hydrogen atoms in different environments. Six of these environments are shown on the structure using letters a, b, c, d, e and f. [Figure of Compound T: C₆H₅-CH₂-CH₂-NH-CH₂-CH₃ with protons labelled a, b, c, d, e, f] Use the letters a, b, c, d, e and f to answer the questions that follow. The questions relate to the proton (¹H) NMR spectrum of T. Proton d does not cause splitting of the peaks for protons c or e under the conditions used. Each answer may be one, or more than one, of the letters a, b, c, d, e and f. Identify the proton or protons with a chemical shift (δ) in the range 6.0 to 9.0.[1]
- (e)(ii)Identify the proton or protons whose peak will disappear if D₂O is added.[1]
- (e)(iii)Identify the proton or protons whose peak is a triplet.[1]
- (e)(iv)Identify the proton or protons with the lowest chemical shift (δ).[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2021). The mark or mark type is shown in brackets.
- [1] PCl₅ OR PCl₃ OR SOCl₂
- [1] amide
- [1] HCl / hydrogen chloride OR C₂H₅NH₃Cl / ethylammonium chloride
- [1] LiAlH₄
- [1] reduction
- [1] relative abundance = 2 carbons x 1.1 x 0.62 = 1.36/1.4 min 2sf
- [1] CH₃CH₂⁺ / C₂H₅⁺
- [1] C₆H₅CH₂⁺
- [1] a
- [1] d
- [1] b, c, f
- [1] f
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