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A-LevelChemistryCarbonyl compounds9701/23 · Oct/Nov 2019 · Q422 Marks

(CH₃)₃CCHO is used in the synthesis of some antibiotics.

  1. (a)(i)Give the name of (CH₃)₃CCHO.[1]
  2. (a)(ii)State the hybridisation of the carbon atom labelled with an asterisk, *. [Figure showing H₃C-C(CH₃)₂-C*HO][1]
  3. (b)(i)Two reaction sequences are shown. [Figure showing reaction scheme with (CH₃)₃CCHO, NaBH₄, S, [O], A, T, U] Reaction 1 is an oxidation reaction. Identify the reagent(s) and conditions for reaction 1.[1]
  4. (b)(ii)A, (CH₃)₃CCO₂H, is a solid at room temperature. B, CH₃CO₂(CH₂)₂CH₃, is an isomer of A. B is a liquid at room temperature. Explain the difference in the physical states of A and B, with reference to any intermolecular forces that may exist.[3]
  5. (b)(iii)Give the balanced equation for the reaction of (CH₃)₃CCHO with NaBH₄ to form S. Use [H] to represent an atom of hydrogen provided by NaBH₄.[1]
  6. (b)(iv)Draw the structure of the organic molecule T that reacts with A, (CH₃)₃CCO₂H, in reaction 2, to form U. Suggest a catalyst for reaction 2. [Box for drawing T] catalyst[2]
  7. (c)(i)X, Y and Z are all isomers of (CH₃)₃CCHO. A summary of some of the reactions and properties of X, Y and Z is shown in the table. | compound | observations with 2,4-DNPH | observations with Fehling's solution | principal absorptions in infra-red spectrum | |---|---|---|---| | X | | no reaction | 1715cm⁻¹ | | Y | | red precipitate | 1730 cm⁻¹ | | Z | no reaction | no reaction | 3200-3600 cm⁻¹; 1630 cm⁻¹; 1050 cm⁻¹ | X and Y each contains a carbonyl group. Complete the table with the expected observations for the reactions of X and Y with 2,4-DNPH.[1]
  8. (c)(ii)Identify the functional group present in Y that causes the recorded observation with Fehling's solution.[1]
  9. (c)(iii)Y has a chiral centre and exists as a pair of optical isomers. State what is meant by the term chiral centre.[1]
  10. (c)(iv)Draw the optical isomers of Y using the conventional three-dimensional representation. [Boxes for drawing isomers][2]
  11. (c)(v)Z, C₅H₁₀O, has a branched carbon chain. It shows geometrical isomerism. Complete the table with the bond responsible for each of the principal absorptions seen in the infra-red spectrum of Z. | principal absorptions in infra-red spectrum | bond responsible | |---|---| | 3200-3600 cm⁻¹ | | | 1630 cm⁻¹ | | | 1050 cm⁻¹ | |[1]
  12. (c)(vi)Draw the skeletal formula of Z.[3]
  13. (c)(vii)X contains a carbonyl group. X reacts with HCN, in the presence of a small amount of NaCN, to form (C₂H₅)₂C(OH)CN as shown. X + HCN → (C₂H₅)₂C(OH)CN Draw the mechanism of the reaction of X with HCN. • Draw the structure of X and the intermediate. • Include all charges, partial charges, lone pairs and curly arrows. [Space for drawing mechanism][3]
  14. (c)(viii)State the role of NaCN in the reaction in (c)(vii).[1]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.

  1. [1] (2,2-)dimethylpropanal
  2. [1] sp²
  3. [1] acidified potassium dichromate[(VI)] AND heat under reflux
  4. [3] M1: A has H-bonding (between molecules) M2: B only has dipole-dipole / VdW forces (between molecules) M3: H-bonding is stronger / requires more energy to overcome
  5. [1] (CH₃)₃CCHO + 2[H] → (CH₃)₃CCH₂OH
  6. [2] M1: Structure of T: HO-CH(CH₃)CH(CH₃)₂ M2: H₂SO₄ / sulfuric acid
  7. [1] orange / red / yellow precipitate (for both X and Y)
  8. [1] Aldehyde
  9. [1] has a carbon / atom attached / bonded to four different atoms / groups / groups of atoms / chains
  10. [2] M1: Correct 3D representation (for Y, (CH₃)₂CHCH(OH)CHO) M2: Correct 3D representation of drawn enantiomer
  11. [1] 3200-3600 cm⁻¹: RO-H / O-H; 1630 cm⁻¹: C=C; 1050 cm⁻¹: C—O
  12. [3] M1: skeletal alkene group AND C5 structure M2: one alcohol group M3: branched chain AND capable of geometrical isomerism (Structure for Z is (CH₃)₂C=CH-CH₂OH)
  13. [3] M1: Correct structure of X and correct dipole on C=O ((C₂H₅)₂C=O) M2: curly arrow from C=O bond to O AND intermediate with CN attached and -ve charge on the O M3: curly arrow from lone pair on CN⁻ to C(=O) in X AND curly arrow from lone pair in the intermediate to H⁺ (Detailed mechanism involving nucleophilic attack by CN⁻ on C=O, formation of alkoxide intermediate, and protonation to form (C₂H₅)₂C(OH)CN)
  14. [1] catalyst

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About this question

Topic
Carbonyl compounds, A-Level Chemistry (syllabus 9701). Structured question, 22 marks.
Source
A-Level Chemistry, Oct/Nov 2019 Paper 2 Variant 3, question 4.

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