The names of many drugs used in medicine often include parts of the names of the functional groups their molecules contain.
- (a)Suggest two functional groups present in a molecule of the drug named chloramphenicol. 1 2[1]
- (b)(i)The drug named ketamine readily reacts with protons as shown. ketamine + H⁺ → [ketamine-H]⁺ State the role of ketamine in this reaction.[1]
- (b)(ii)Ketamine gives an orange precipitate with 2,4-dinitrophenylhydrazine (2,4-DNPH). Suggest the functional group in the ketamine molecule responsible for this observation.[1]
- (b)(iii)The mass spectrum of ketamine is determined. Two peaks close to the molecular ion peak, M, are observed with the relative abundances shown in the table. peak m/e relative abundance M 237 100.0 M+1 238 14.3 M+2 239 33.3 Use the numbers in the table to show that there are 13 carbon atoms in a ketamine molecule.[1]
- (b)(iv)In addition to carbon and hydrogen atoms, each molecule of ketamine contains one atom of each of three different elements. These are called heteroatoms. One of these heteroatoms is a halogen. Use the figures in the table to suggest the identity of this halogen. Explain your answer.[1]
- (b)(v)Another peak in the mass spectrum of ketamine has an m/e value of 240. Predict the relative abundance of this peak.[1]
- (b)(vi)Use the information in (b) to complete the molecular formula of ketamine by working out the identities of the three different heteroatoms and the number of hydrogen atoms present. C13H[1]
- (c)(i)Suggest the number of peaks in the carbon-13 NMR spectrum of neramexane.[1]
- (c)(ii)The proton (¹H) NMR spectrum of neramexane in CDCl3 shows five peaks with the following chemical shifts (δ). δ/ppm number of protons responsible splitting pattern (singlet, doublet, triplet, quartet or multiplet) 0.9 singlet 1.2 3 1.4 2 1.7 4 2.2 broad singlet Complete the table.[4]
- (c)(iii)Use the Data Booklet and the table in (c)(ii) to complete the assignment of the correct δ values to each of the circled hydrogen atoms on the structure of neramexane.[2]
- (c)(iv)One of the peaks in the proton (¹H) NMR spectrum disappears when the sample is shaken with D₂O. Identify the peak and explain why it disappears.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2019). The mark or mark type is shown in brackets.
- [1] Any two of: chloro / amine / amino / alcohol / hydroxyl / phenol / benzene / phenyl ring / aryl / arene
- [1] ketamine is acting as a base
- [1] carbonyl group
- [1] n = (100/1.1) x (14.3 / 100) = 13.0_OR_n = (14.3 / 1.1) = 13.0
- [1] the ratio of the (M:M+2) peaks is 3:1 AND halogen is chlorine / Cl
- [1] relative abundance = 14.3/3 = 4.77 (4.8) OR RA = 14.3 × 33.3 / 100 = 4.76 (4.8)
- [1] C₁₃H₁₆NOCl
- [1] six
- [4] M1 peak at δ 0.9 is due to 12 Η
- M2 peak at 2.2 is due to 2 Η
- M3/M4 peaks at 1.2, 1.4 and 1.7 are all singlets
- [2] (diagram with correct assignments)
- [1] NH / NH₂ protons AND exchange with D₂O / D OR -NH₂ + D₂O → -ND₂ + H₂O
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