(a) Ethanedioate ions, C2O42-, are bidentate ligands. Explain what is meant by the term ligand.
- (a)Explain what is meant by the term ligand. [1][1]
- (b)Cr³+(aq) and C2O42-(aq) ions form the complex ion [Cr(C2O4)2(H2O)2]. Draw two stereoisomers of this complex ion. You may use [Figure: C2O42- represented by a curved line with two oxygen atoms linked to a central dot] to represent C2O42-. [2][2]
- (c)The solubility of calcium ethanedioate, CaC2O4, is 6.65 × 10-³gdm-³ at 298 K.
- (c)(i)Write an expression for the solubility product, Ksp, of CaC2O4. Include its units. Ksp = ..................................................... units = ................................. [2][2]
- (c)(ii)Calculate the numerical value of Ksp CaC2O4 at 298 K. Give your answer in standard form to two significant figures. Ksp CaC2O4 = ................................. [2][2]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.
- [1] species that forms dative bond(s) to a (central) metal atom/ion
- [1] any two structures
- [1] Ksp = [Ca2+][C2O42-]
- [1] units mol² dm¯⁶
- [1] [Ca²+] = [C2O42-] = 6.65 × 10¯³/128.1 = 5.19 × 10-5 mol dm¯³
- [1] Ksp = (5.19 × 10-5)² = 2.7 × 10¯⁹ mol² dm¯⁶
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