Qualitative Analysis Where reagents are selected for use in a test, the full name or correct formula of the element or compound must be given. At each stage of any test you are to record details of the following: • colour changes seen; • the formation of any precipitate and its solubility in an excess of the reagent added; • the formation of any gas and its identification by a suitable test. You should indicate clearly at what stage in a test a change occurs. If any solution is warmed, a boiling tube must be used. Rinse and reuse test-tubes and boiling tubes where possible. No additional tests for ions present should be attempted. 3 (a) FA 4 is a solution of a transition metal compound dissolved in acid. Carry out the following tests on FA 4 and record your observations.
- (a)test To a 1 cm depth of FA 4 in a test-tube, add a 1 cm depth of potassium iodide, then add aqueous sodium thiosulfate. To a 3 cm depth of FA 4 in a boiling tube, add a spatula measure of zinc powder, FA 3. If no reaction occurs, carefully warm the mixture. Leave the mixture for 5–15 minutes, observing the mixture occasionally. Keep the mixture of FA 4 and FA 3 for use in (c). The solution formed from the mixture is FA 6. Complete part (b) while FA 4 and FA 3 continue reacting.[5]
- (b)(i)FA 5 is the acid used to make FA 4. The anion in FA 5 is listed in the Qualitative Analysis Notes. List the reagents you would use to identify this anion and state which acid the reagents are testing for.[2]
- (b)(ii)Carry out one of your tests in (i) and record your observations. Give the formula of the anion present in FA 5. Write ‘unknown' if your test could not positively identify this anion. observations[2]
- (c)Carry out the following tests on FA 6 (the solution formed in (a)). test To a 1 cm depth of FA 6 in a test-tube, add acidified potassium manganate(VII) a few drops at a time until in excess. At this stage the solution will be pink. To a 1 cm depth of FA 6 in a test-tube, add a 1 cm depth of FA 4.[3]
- (d)(i)State the type of reaction occurring in (c) when acidified potassium manganate(VII) was added to FA 6. Give a reason for your answer.[2]
- (d)(ii)The ion present in FA 4 when in acidic solution is usually written as MO2+ where M represents the transition metal. Calculate the oxidation state of M in MO2+. oxidation state of M = ..............................................[1]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.
- [1] + KI: Solution (turns) brown / red-brown / orange-brown / yellow-brown or black ppt/solid
- [1] + sodium thiosulfate: (Solution) turns blue (Allow blue-green / green solution; ignore ‘cloudy' or 'milky'.)
- [2] + Zn: Expected solution colour changes: yellow → green → blue → green → violet (3 colours correct (in the correct order) = 2 marks, 2 colours correct (in the correct order) = 1 mark)
- [1] bubbles / effervescence/ fizzing or gas pops with lighted splint
- [1] Selects BaCl2 / Ba(NO3)2 (as reagent for sulfate)
- [1] States H2SO4 (as the acid for which the anion is being tested)
- [1] White ppt with Ba2+ / no reaction with any other appropriate anion tests listed in (b)(i)
- [1] SO42- / 'unknown' (from appropriate observation)
- [2] + KMnO4: Expected colour changes of solution: violet / final colour given in 3(a) → green → blue → green → yellow (allow orange) → pink / purple (3 colours correct (in the correct order) = 2 marks, 2 colours correct (in the correct order) = 1 mark)
- [1] + FA 4: Turns blue / green (ignore state)
- [1] Redox
- [1] manganate(VII) / MnO4⁻ (allow KMnO4) is an oxidising agent / is reduced / changes from purple to colourless (allow is decolourised) or different colours indicate different oxidation states
- [1] (+) 5
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