Ethanedioate ions, ⁻O₂CCO₂⁻, are bidentate ligands. The abbreviation ed²⁻ can be used to represent ethanedioate ions.
- (a)Complete the following electronic structures. • the iron atom, Fe 1s²2s²2p⁶ .............................. • the iron(III) ion, Fe³⁺ 1s²2s²2p⁶ ..............................[1]
- (b)Solutions of iron(III) salts are acidic due to the equilibrium shown. [Fe(H₂O)₆]³⁺(aq) ⇌ [Fe(H₂O)₅(OH)]²⁺(aq) + H⁺(aq) Kₐ = 8.9 × 10⁻⁴ mol dm⁻³ Calculate the pH of a 0.25 mol dm⁻³ FeCl₃ solution. pH = ..............................[2]
- (c)(i)What is meant by the term stability constant, Kstab?[1]
- (c)(ii)Use the data in the table to predict the formula of the complex formed in the greatest amount when • a solution containing equal concentrations of both F⁻ and SCN⁻ ions is added to Fe³⁺(aq), • a solution containing equal concentrations of both Fe³⁺ and Hg²⁺ ions is added to Cl⁻(aq).[1]
- (d)The complex [Fe(ed)₂Cl₂]³⁻ can be formed according to the equation shown. [Fe(H₂O)₄Cl₂]⁺(aq) + 2ed²⁻(aq) ⇌ [Fe(ed)₂Cl₂]³⁻(aq) + 4H₂O(l) Write the expression for the equilibrium constant, Kstab, and state its units. Kstab = .............................. units ..............................[2]
- (e)(i)Complete the three-dimensional diagrams to show the three stereoisomers of [Fe(ed)₂Cl₂]³⁻. You may use [symbol for ethanedioate] to represent ed²⁻.[3]
- (e)(ii)Give the letters of two isomers of [Fe(ed)₂Cl₂]³⁻ which are geometrical isomers of each other.[1]
- (e)(iii)Give the letters of the two isomers of [Fe(ed)₂Cl₂]³⁻ which show optical isomerism.[1]
- (e)(iv)Give the letter of the isomer which has no dipole moment.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- [1] (a) Fe atom= (1s²2s²2p⁶)3s²3p⁶3d⁶4s²
- [1] (a) Fe³⁺ ion= (1s²2s²2p⁶)3s²3p⁶3d⁵
- [1] (b) ([H⁺]² = = 8.9 × 10⁻⁴ × 0.25 or 2.225 × 10⁻⁴)
- [1] (b) [H⁺] = 0.0149
- [1] (b) pH = -log(0.0149) = 1.83
- [1] (c)(i) (Kstab is) the equilibrium constant for the formation of a complex (ion) (in a solvent from its constituent ions/molecules)
- [1] (c)(ii) [Fe(H₂O)₅F]²⁺ and [Hg(H₂O)₅Cl]⁺
- [1] (d) Kstab = [Fe(ed)₂Cl₂³⁻] / ([Fe(H₂O)₄Cl₂⁺][ed]²)
- [1] (d) mol⁻² dm⁶
- [1] (e)(i) [Diagram for isomer A (cis with Cl-Cl trans to each other, bidentate ed ligands are cis to each other)]
- [1] (e)(i) [Diagram for isomer B (cis with Cl-Cl cis to each other, bidentate ed ligands are cis to each other, enantiomer of A)]
- [1] (e)(i) [Diagram for isomer C (trans with Cl-Cl trans to each other, bidentate ed ligands are cis to each other)]
- [1] (e)(ii) any cis isomer and the trans isomer identified
- [1] (e)(iii) both correct cis isomers identified
- [1] (e)(iv) trans isomer identified
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