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A-LevelChemistryChemical energetics9701/23 · Oct/Nov 2017 · Q122 Marks

Ammonia, NH3, is manufactured from nitrogen and hydrogen by the Haber process. N2(g) + 3H2(g) ⇌ 2NH3(g) ΔH = –92 kJ mol–1

  1. (a)(i)Some bond energies are given. N=N = 944 kJ mol–1 H–H = 436 kJ mol–1 (i) Explain the meaning of the term bond energy.[2]
  2. (a)(ii)(ii) Use the data to calculate a value for the N–H bond energy. You must show your working. N–H bond energy = .............................................. kJ mol–1[2]
  3. (b)(i)The Haber process is usually carried out at a temperature of approximately 400°C in the presence of a catalyst. Changing the temperature affects both the rate of production of ammonia and the yield of ammonia. The Boltzmann distribution for a mixture of nitrogen and hydrogen at 400 °C is shown. Ea represents the activation energy for the reaction. [Figure 1.1: Boltzmann distribution graph] (i) Using the same axes, sketch a second curve to indicate the Boltzmann distribution at a higher temperature.[2]
  4. (b)(ii)(ii) With reference to the Boltzmann distribution, state and explain the effect of increasing temperature on the rate of production of ammonia.[3]
  5. (b)(iii)(iii) State and explain the effect of increasing temperature on the yield of ammonia. Use Le Chatelier's principle to explain your answer.[3]
  6. (c)(i)At a pressure of 2.00 × 10⁷ Pa, 1.00 mol of nitrogen, N2(g), was mixed with 3.00 mol of hydrogen, H2(g). The final equilibrium mixture formed contained 0.300 mol of ammonia, NH3(g). (i) Calculate the amounts, in mol, of N2(g) and H2(g) in the equilibrium mixture. N2(g) = .............................................. mol H2(g) = .............................................. mol[2]
  7. (c)(ii)(ii) Calculate the partial pressure of ammonia, pNH3, in the equilibrium mixture. Give your answer to three significant figures. pNH3 = .............................................. Pa[3]
  8. (d)(i)In another equilibrium mixture the partial pressures are as shown. substance partial pressure/Pa N2(g) 2.20 × 10⁶ H2(g) 9.62 × 10⁵ NH3(g) 1.40 × 10⁴ (i) Write the expression for the equilibrium constant, Kp, for the production of ammonia from nitrogen and hydrogen. Kp =[1]
  9. (d)(ii)(ii) Calculate the value of Kp for this reaction. State the units. Kp = .............................................. units = ..............................................[2]
  10. (d)(iii)(iii) This reaction is repeated with the same starting amounts of nitrogen and hydrogen. The same temperature is used but the container has a smaller volume. State the effects, if any, of this change on the yield of ammonia and on the value of Kp. effect on yield of ammonia ........................................................................................................................ effect on value of Kp ....................................................................................................................................[2]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.

  1. [1] energy needed / required to break a mole of (covalent) bonds
  2. [1] (All) in the gaseous state
  3. [1] −92 = {944 + 3(436)} – 6E(N-H)
  4. [1] E(N-H) = (+)390.7 / 390.67 /391
  5. [1] general shape of the curve and peak are displaced to right of original line and starts at origin
  6. [1] the peak is lower and curve crosses once only finishing above original line
  7. [1] rate increases AND explanation in terms of collisions
  8. [1] (at higher T) area above Ea is greater OR (at higher T) more molecules with E > Ea
  9. [1] higher frequency of successful collisions OR more successful collisions per unit time / higher chance of successful collisions per unit time / higher proportion of successful collisions per unit time
  10. [1] reduces yield (of ammonia).
  11. [1] (increasing T) shifts equilibrium (reaction) to the left / in the reverse direction / towards N2 and H2 / towards reactants / in endothermic direction
  12. [1] to oppose the change OR oppose the increase in temperature OR to absorb the (additional) heat / energy OR decrease the temperature
  13. [1] N2 = 0.850 (mol)
  14. [1] H2 = 2.55 (mol)
  15. [1] NTOTAL = 3.7 mol
  16. [1] mol fraction of NH3 = 0.3/3.7
  17. [1] pNH3 = 2 × 10⁷ × (0.3/3.7) = 1.62 × 10⁶
  18. [1] Kp= pNH3² / PN2 × pH2³
  19. [1] Kp = 1.(00)× 10⁻¹⁶
  20. [1] Pa⁻²
  21. [1] (yield of ammonia) increases
  22. [1] (value of Kp) stays the same

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About this question

Topic
Chemical energetics, A-Level Chemistry (syllabus 9701). Structured question, 22 marks.
Source
A-Level Chemistry, Oct/Nov 2017 Paper 2 Variant 3, question 1.

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