Ethane-1,2-diol, HOCH₂CH₂OH, reacts with an excess of ethanoic acid, CH₃CO₂H, in the presence of an acid catalyst. A compound is formed with the molecular formula C₆H₁₀O₄. What is the structure of this compound?
✓ Correct answer
C: CH₃CO₂CH₂CH₂OCOCH₃
Practise more questions on this topic
Oracle Prep sorts past-paper questions by topic, so you can drill Carboxylic acids and derivatives and see which topics are most likely to come up next.
Sign up free →