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A-LevelChemistryCarboxylic acids and derivatives9701/42 · May/June 2025 · Q99 Marks

The structures of the amino acids serine and lysine are shown in Fig. 9.1. [Figure 9.1]

  1. (a)Draw the structure for the dipeptide, ser-lys, with molecular formula C9H19N3O4. The peptide functional group formed should be displayed.[2]
  2. (b)(i)The isoelectric point of serine is 5.7 and of lysine is 9.7. State what is meant by isoelectric point.[1]
  3. (b)(ii)A mixture of serine, lysine and ser-lys is analysed by electrophoresis using a buffer at pH 5.7. [Figure 9.2] Draw and label three spots on Fig. 9.2 to indicate the predicted position of each of these three species, serine, lysine and ser-lys, after electrophoresis. Explain your answer.[3]
  4. (c)(i)Fig. 9.3 shows the synthesis of compound R from compound P. [Figure 9.3] Draw the structure of Q in Fig. 9.3.[1]
  5. (c)(ii)State the reagents and conditions for steps 1 and 2 in Fig. 9.3. step 1 ............................................ step 2 ............................................[2]

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Mark scheme

Marking points from the official mark scheme (May/June 2025). The mark or mark type is shown in brackets.

  1. [1] M1: correct displayed peptide bond with an adjacent C(H) (to CO) and C(H) to NH
  2. [1] M2: rest of the dipeptide correct
  3. [1] pH at which a molecule has no overall charge / no net charge
  4. [1] M1: correct relative positions of the spots drawn
  5. [1] M2: ser not moved AND as it is a zwitterion / neutral OR ser-lys / lys AND move towards negative (pole) as they are positively charged
  6. [1] M3: lys moves the furthest / fastest AND as it has the lower Mr / smaller size (than ser-lys)
  7. [1] (diagram showing an open chain, HOOC-CH(NHCH3)-CH2-CH(OH)-CH2OH)
  8. [1] M1: step 1 aqueous AND HCl/ H2SO4 AND heat/reflux[1]
  9. [1] M2: step 2 conc. H2SO4 catalyst AND high temp / heat

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About this question

Topic
Carboxylic acids and derivatives, A-Level Chemistry (syllabus 9701). Structured question, 9 marks.
Source
A-Level Chemistry, May/June 2025 Paper 4 Variant 2, question 9.

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