Methyl red can be synthesised as shown in Fig. 7.1. [Figure 7.1 showing the reaction scheme starting from compound P (2-nitrobenzoic acid), going through step 1 to Q, then Q reacts to form R and S (both are reactants in step 3), then R and S react in step 3 to form Methyl red. Structure P is benzoic acid with a nitro group at the ortho position.]
- (a)(i)Give the systematic name of P.[1]
- (a)(ii)P can be synthesised as shown in Fig. 7.2. [Figure 7.2 showing methylbenzene (toluene) reacting to form 2-nitromethylbenzene, then this reacting to form P (2-nitrobenzoic acid)] Suggest reagents and conditions for this reaction.[1]
- (a)(iii)A student attempts to synthesise P by an alternative route, as shown in Fig. 7.3. Compound T is the major product in this reaction rather than P. [Figure 7.3 showing benzoic acid reacting with conc. HNO₃ and conc. H₂SO₄ to form T (3-nitrobenzoic acid) and P (2-nitrobenzoic acid as minor)] Explain why T is the major product in this reaction.[1]
- (b)(i)S reacts in a similar way to phenol in step 3. Draw the structures of Q, R and S in the boxes in Fig. 7.1.[3]
- (b)(ii)Suggest reagents and conditions for steps 1 and 2 in Fig. 7.1. step 1 step 2[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [1] 2-nitrobenzoic acid OR 2-nitrobenzenecarboxylic acid
- [1] hot/reflux/heat AND (alkaline / acidified / neutral) MnO4¯/ KMnO4
- [1] COOH / carboxyl group is electron-withdrawing / electronegative AND 3- and 5-/meta- directing
- [3] Q: 2-aminobenzoic acid
- R: Benzenediazonium salt with -COOH ortho
- S: N,N-dimethylphenylamine
- [3] M1 step 1: Fe / Sn, conc. HCI
- M2 step 2: HNO2 OR NaNO2 AND HCI
- M3 step 1: heat / reflux / hot AND step 2: ≤10 °C
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