Carbon disulfide, CS₂, is flammable and reacts readily with oxygen, as shown in reaction 1. reaction 1 CS₂(g) + 3O₂(g) → CO₂(g) + 2SO₂(g) Table 3.1 shows the standard enthalpy of formation, ∆H°f, and the standard entropy, S°, for some substances. Table 3.1 CS₂(g) O₂(g) CO₂(g) SO₂(g) ∆H°f / kJ mol⁻¹ 116.7 0.0 -393.5 -296.8 S° / J K⁻¹ mol⁻¹ 237.8 205.2 213.8 248.2 Calculate the standard Gibbs free energy change, ∆G°, in kJ mol⁻¹, for reaction 1 at 25°C. ∆G° = ................................... kJ mol⁻¹ [3]
- (a)Carbon disulfide, CS₂, is flammable and reacts readily with oxygen, as shown in reaction 1. reaction 1 CS₂(g) + 3O₂(g) → CO₂(g) + 2SO₂(g) Table 3.1 shows the standard enthalpy of formation, ∆H°f, and the standard entropy, S°, for some substances. Table 3.1 CS₂(g) O₂(g) CO₂(g) SO₂(g) ∆H°f / kJ mol⁻¹ 116.7 0.0 -393.5 -296.8 S° / J K⁻¹ mol⁻¹ 237.8 205.2 213.8 248.2 Calculate the standard Gibbs free energy change, ∆G°, in kJ mol⁻¹, for reaction 1 at 25°C. ∆G° = ................................... kJ mol⁻¹ [3][3]
- (b)Carbon disulfide reacts with chlorine to form tetrachloromethane, as shown in reaction 2. reaction 2 CS₂ + 3Cl₂ → CCl₄ + S₂Cl₂ ∆H° = −261.6 kJ mol⁻¹ ∆S° = −365.5 J K⁻¹ mol⁻¹ Calculate the maximum temperature, in K, for reaction 2 to be feasible. temperature = ................................... K [2][2]
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- [3] M1 ∆S® = (213.8 + 2 × 248.2) − (237.8 + 3 × 205.2)
- AS° = −143.2 (JK-1 mol-1)
- Μ2 ΔΗ° = (−393.5 + 2 x −296.8) – (116.7)
- ΔΗ͂ = −1103.8 (kJ mol-1)
- M3 AG = ∆H - TAS
- ∆G° = −1103.8 – (298 × −0.1432) = −1061.1 to –1061.4 (kJ mol-1) ecf min 3sf
- [2] M1 AG = ∆H – TAS AND AG = 0
- OR T = ∆H / AS® [1]
- M2 T = 261.6 ÷ 0.3655 = 715.7/716/715 K min 3sf
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