Describe the trend in the solubility of the sulfates of magnesium, calcium and strontium. Explain your answer. most soluble > > least soluble
- (a)Describe the trend in the solubility of the sulfates of magnesium, calcium and strontium. Explain your answer. most soluble > > least soluble[4]
- (b)Define lattice energy, ΔΗlatt·[2]
- (c)State and explain the main factors that affect the magnitude of lattice energies.[2]
- (d)(i)Table 1.1 shows some energy changes. Table 1.1 energy change value/kJmol⁻¹ standard enthalpy change of atomisation of potassium +89 first ionisation energy of potassium +419 second ionisation energy of potassium +3070 standard enthalpy change of atomisation of sulfur +279 S-S bond energy +265 first ionisation energy of sulfur +1000 second ionisation energy of sulfur +2260 first electron affinity of sulfur -200 second electron affinity of sulfur +640 standard enthalpy change of formation of potassium sulfide, K₂S(s) -381 Born-Haber cycles can be used to determine the lattice energies of ionic compounds. Complete the Born–Haber cycle in Fig. 1.1 for potassium sulfide, K₂S(s). Include state symbols for all of the species. [Figure 1.1][3]
- (d)(ii)Calculate the lattice energy, ΔHlatt, of K₂S(s) using relevant data from Table 1.1. Show your working. ΔHlatt of K₂S(s) = ................................... kJ mol⁻¹ [2][2]
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Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [4] M1 magnesium > calcium > strontium
- M2 ∆Hlatt and ∆Hhyd both become less exothermic / less negative
- M3 ∆Hlatt changes less OR ∆Hhyd is dominant factor
- M4 ∆Hsol becomes less exothermic / less negative / more positive / more endothermic
- [2] M1 ΔΗ/energy change when 1 mole of an ionic solid / compound is formed
- M2 from gaseous ions (under standard conditions)
- [2] M1 as ionic radii increases AND AHlatt less exothermic
- M2 as ionic charge increases AND ∆Hlatt increases/more exothermic
- [3] 2K+(g) + S2-(g).
- 2K+(g) + S(g) + 2e-
- 2K+(g) + S-(g) + e-
- 2K(g) + S(g) OR 2K+(g) + S(s) + 2e-
- 2K(g) + S(s) OR 2K(s) + S(g)
- any two [1] any three [2] all four [3]
- [2] M1 selection of ONLY six correct values (-381, 89, 419, 279, –200, 640) AND use of × 2 as only multiplier with K
- M2 correct evaluation of data used ecf
- -381 = (89 × 2) + (419 × 2) + 279 + (−200) + 640 + ∆Η°latt
- ΔΗ°latt = −2116 (kJ mol-1)
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