Define Le Chatelier's principle.
- (a)Define Le Chatelier's principle.[2]
- (b)Reaction 1 describes the reversible reaction between yellow Fe3+(aq) and colourless SCN-(aq) to produce red FeSCN2+(aq). reaction 1 Fe3+(aq) + SCN-(aq) ⇋ FeSCN2+(aq) ΔH = -x kJ mol-1 yellow colourless red A mixture of Fe3+(aq), SCN-(aq) and FeSCN2+(aq) is at equilibrium at 20°C. The temperature of this mixture is then increased to 50 °C and allowed to reach equilibrium. Deduce the changes that occur, if any, in the equilibrium mixture at 50°C compared to the equilibrium mixture at 20 °C. • change in appearance • change in relative concentration of FeSCN2+(aq) • change in value of the equilibrium constant, Kc[3]
- (c)In another experiment, equimolar amounts of Fe3+(aq) and SCN¯(aq) are mixed together and allowed to reach equilibrium. The total volume of the mixture is 25.0cm³. reaction 1 Fe3+(aq) + SCN-(aq) ⇋ FeSCN2+(aq) At equilibrium the mixture contains: • [SCN¯] = 1.30 × 10-3moldm−3 • [FeSCN2+] = 0.300 × 10−3moldm−3.
- (c)(i)Calculate the initial amount, in mol, of Fe3+(aq) added to SCN-(aq) to produce this mixture. initial amount of Fe3+(aq) = .............................................. mol[2]
- (c)(ii)Calculate Kc for reaction 1 and state its units. Show your working. Kc = .............................................. units ..............................................[2]
Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [2] M1 (if a change in conditions occurs) the equilibrium shifts
- M2 to minimise the change in conditions
- [3] M1 change in appearance: paler red / more yellow / less orange
- M2 change in relative concentration of FeSCN2+(aq): lower
- M3 change in value of the equilibrium constant, Kc: lower
- [2] M1 deduce the concentration of SCN- present in initial mixture: [SCN-eq'm] = [Fe3+ eq'm] = [original SCN-] – [FeSCN2+ produced]
- 1.30 x 10-3 + 0.300 × 10-3 = 1.60 × 10-3 mol dm-3
- M2 find initial amount of Fe3+ initially: M1 × 25/1000 = amount of Fe3+ added initially = 4.00 × 10-5 (mol)
- [2] M1 value for Kc = 178
- M2 units = mol-1 dm³
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