Y is formed from X in a single-step reaction, as shown in Fig. 5.1. [Figure 5.1]
- (a)Deduce the empirical formula of Y.[1]
- (b)The formation of Y from X requires the addition of a suitable reducing agent.
- (b)(i)Construct an equation using molecular formulae and [H] for the reaction in Fig. 5.1. Use [H] to represent one atom of hydrogen from the reducing agent.[1]
- (b)(ii)Identify a suitable non-gaseous reducing agent for the formation of Y from X.[1]
- (c)Complete Table 5.1 to show the number of sp² and sp³ hybridised carbon atoms in a molecule of X. Table 5.1 type of hybridisation sp² sp³ number of carbon atoms in X[2]
- (d)Complete Table 5.2 with the expected observations that occur when the reagents shown are added to separate solutions of X and Y. Do not refer to temperature changes in your answer. Table 5.2 reagent observation on addition to X observation on addition to Y aqueous sodium carbonate 2,4-dinitrophenylhydrazine (2,4-DNPH reagent) alkaline aqueous iodine[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.
- [1] C3H7O
- [1] C6H10O3 + [6H] → C6H14O2 + H2O
- [1] LiAlH4 (in dry ether)
- [2] sp2: 2, sp3: 4
- [3] (Table entries) sodium carbonate solution: X: effervescence, Y: no change; 2,4-DNPH: X: orange precipitate, Y: no change; alkaline aqueous iodine: X: yellow precipitate, Y: yellow precipitate. Two correct for one mark, four correct for two marks, six correct for three marks
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