Describe structural isomerism.
- (a)Describe structural isomerism.[1]
- (b)(i)A and B are structural isomers with molecular formula C5H10O. They are both straight-chained molecules with only one functional group. Table 5.1 describes observations when separate samples of A and B are added to different reagents. Table 5.1 reagent | A | B ---|---|--- 2,4-dinitrophenylhydrazine (2,4-DNPH reagent) | orange precipitate appears | orange precipitate appears Tollens' reagent | silver mirror appears | no reaction alkaline I2(aq) | no reaction | no reaction Name the functional group present in both A and B.[1]
- (b)(ii)Draw the structures of A and B in the boxes. A B[2]
- (c)(i)C is a structural isomer of A and B. C is straight chained and has two functional groups. C shows only one type of stereoisomerism. Table 5.2 describes observations when separate samples of C are added to different reagents. Table 5.2 reagent | C ---|--- 2,4-dinitrophenylhydrazine (2,4-DNPH reagent) | no reaction Br2(aq) | orange to colourless alkaline I2(aq) | yellow precipitate appears Draw the structure of C in the box. C[2]
- (c)(ii)Name the type of stereoisomerism shown by molecules of C.[1]
- (d)(i)D reacts in the presence of a sulfuric acid catalyst to form E and water. The structure of E is shown in Fig. 5.1. [Figure 5.1] Name the functional group present in E.[1]
- (d)(ii)Identify the type of reaction that occurs when D reacts to form E.[1]
- (d)(iii)Draw the structure of D in the box. D[1]
- (d)(iv)The infrared spectrum of E is shown in Fig. 5.2. [Figure 5.2] Table 5.3 bond | functional groups containing the bond | characteristic infrared absorption range (in wavenumbers)/cm⁻¹ ---|---|--- C-O | hydroxy, ester | 1040–1300 C=C | aromatic compound, alkene | 1500–1680 C=O | amide | 1640–1690 carbonyl, carboxyl | 1670–1740 ester | 1710–1750 C≡N | nitrile | 2200–2250 C-H | alkane | 2850–2950 N-H | amine, amide | 3300–3500 O-H | carboxyl | 2500–3000 hydroxy | 3200–3600 Use Fig. 5.2 and Table 5.3 to predict two differences in the absorptions above 1500cm⁻¹ of the infrared spectrum of D compared to E. Explain your answer.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.
- [1] molecules / isomers with the same molecular formula / same number of atoms of each element AND different structural formulae / different structures
- [1] carbonyl (group)
- [2] A: CH3CH2CH2CH2CHO B: CH3CH2COCH2CH3
- [2] M1 CH3CH(OH) present M2 five carbons in a straight chain AND molecular formula C5H10O AND 1 C=C structure which shows only one type of stereoisomerism
- [1] optical
- [1] ester
- [1] condensation
- [1] HO-(CH2)4-COOH
- [2] Any two of the following differences in spectra D compared to E: bond | functional group | value or range of values of absorbance inclusive (cm⁻¹) ---|---|--- E | C=O/C double bond to O | (ester) | 1710–1750 D | C=O | (carboxy(l)) | 1670–1740 D | O-H OR OH bond | (carboxy(l)) | 2500–3000 D | O-H OR OH bond | (hydroxy(l) OR alcohol) | 3200–3600
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →