Procaine is used as an anaesthetic in medicine. It can be synthesised from methylbenzene in five steps as shown in Fig. 7.1. [Figure 7.1 showing synthesis scheme]
- (a)(i)Name all the functional groups present in procaine.[1]
- (a)(ii)A molecule of procaine has 13 carbon atoms. State the number of carbon atoms that are sp, sp² and sp³ hybridised in procaine. sp carbons = sp² carbons = sp³ carbons =[1]
- (b)The proton (¹H) NMR spectrum of procaine dissolved in D₂O is recorded. Predict the number of peaks observed.[1]
- (c)State why procaine can act as a base.[1]
- (d)(i)Compound X can be synthesised in two steps from methylbenzene. [Figure 7.2 showing partial synthesis] Draw the structure of compound W in the box provided.[1]
- (d)(ii)State the reagents and conditions for step 1 and step 2. step 1 step 2[2]
- (e)Procaine is synthesised in three steps from X. Suggest the reagents and conditions for step 4 and for step 5 in Fig. 7.1. step 4 step 5[3]
- (f)(i)Explain what is meant by partition coefficient, K_pc.[2]
- (f)(ii)The partition coefficient of procaine between octan-1-ol and water is 1.77. Octan-1-ol and water are immiscible. A solution containing 0.500 g of procaine in 75.0 cm³ of water is shaken with 50.0 cm³ of octan-1-ol. Calculate the mass of procaine that is extracted into the octan-1-ol. mass of procaine extracted =[2]
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Mark scheme
Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.
- [1] phenylamine AND amine AND ester
- [1] sp carbons = 0, sp² carbons = 7, sp³ carbons = 6
- [1] 6
- [1] lone pair on the N can accept a proton
- [1] (Structure as shown in MS: methylbenzene with a nitro group, e.g., p-nitrotoluene)
- [2] step 1 M1 concentrated HNO3 and H2SO4
- step 2 M2 hot (alkaline) KMnO4 (followed by addition of H+)
- [3] step 4 M1 HOCH2CH2N(CH2CH3)2
- step 5 M2 Sn AND HCl
- M3 concentrated (HCl) AND heat / reflux
- [2] M1 ratio of the concentration of a solute in two solvents
- M2 at equilibrium
- [2] M1 Kpc = [procaine]oct/ [procaine]water
- 1.77 = (x/50)/(0.5 – x/ 75)
- M2 1.77 = 1.5x/0.5 - x
- 0.885-1.77x = 1.5x
- x = 0.271 g min 2sf
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