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A-LevelChemistryOrganic synthesis9701/41 · May/June 2022 · Q714 Marks

Procaine is used as an anaesthetic in medicine. It can be synthesised from methylbenzene in five steps as shown in Fig. 7.1. [Figure 7.1 showing synthesis scheme]

  1. (a)(i)Name all the functional groups present in procaine.[1]
  2. (a)(ii)A molecule of procaine has 13 carbon atoms. State the number of carbon atoms that are sp, sp² and sp³ hybridised in procaine. sp carbons = sp² carbons = sp³ carbons =[1]
  3. (b)The proton (¹H) NMR spectrum of procaine dissolved in D₂O is recorded. Predict the number of peaks observed.[1]
  4. (c)State why procaine can act as a base.[1]
  5. (d)(i)Compound X can be synthesised in two steps from methylbenzene. [Figure 7.2 showing partial synthesis] Draw the structure of compound W in the box provided.[1]
  6. (d)(ii)State the reagents and conditions for step 1 and step 2. step 1 step 2[2]
  7. (e)Procaine is synthesised in three steps from X. Suggest the reagents and conditions for step 4 and for step 5 in Fig. 7.1. step 4 step 5[3]
  8. (f)(i)Explain what is meant by partition coefficient, K_pc.[2]
  9. (f)(ii)The partition coefficient of procaine between octan-1-ol and water is 1.77. Octan-1-ol and water are immiscible. A solution containing 0.500 g of procaine in 75.0 cm³ of water is shaken with 50.0 cm³ of octan-1-ol. Calculate the mass of procaine that is extracted into the octan-1-ol. mass of procaine extracted =[2]

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Mark scheme

Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.

  1. [1] phenylamine AND amine AND ester
  2. [1] sp carbons = 0, sp² carbons = 7, sp³ carbons = 6
  3. [1] 6
  4. [1] lone pair on the N can accept a proton
  5. [1] (Structure as shown in MS: methylbenzene with a nitro group, e.g., p-nitrotoluene)
  6. [2] step 1 M1 concentrated HNO3 and H2SO4
  7. step 2 M2 hot (alkaline) KMnO4 (followed by addition of H+)
  8. [3] step 4 M1 HOCH2CH2N(CH2CH3)2
  9. step 5 M2 Sn AND HCl
  10. M3 concentrated (HCl) AND heat / reflux
  11. [2] M1 ratio of the concentration of a solute in two solvents
  12. M2 at equilibrium
  13. [2] M1 Kpc = [procaine]oct/ [procaine]water
  14. 1.77 = (x/50)/(0.5 – x/ 75)
  15. M2 1.77 = 1.5x/0.5 - x
  16. 0.885-1.77x = 1.5x
  17. x = 0.271 g min 2sf

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About this question

Topic
Organic synthesis, A-Level Chemistry (syllabus 9701). Structured question, 14 marks.
Source
A-Level Chemistry, May/June 2022 Paper 4 Variant 1, question 7.

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