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A-LevelChemistryHydrocarbons9701/42 · May/June 2021 · Q611 Marks

There are four possible structural isomers of C8H10 that contain a benzene ring. Draw the skeletal formulae of the four structural isomers in the appropriate boxes. The number of peaks observed in the carbon-13 (13C) NMR spectrum of each compound is given. isomer 1 three peaks in 13C NMR isomer 2 four peaks in 13C NMR isomer 3 five peaks in 13C NMR isomer 4 six peaks in 13C NMR

  1. (a)There are four possible structural isomers of C8H10 that contain a benzene ring. Draw the skeletal formulae of the four structural isomers in the appropriate boxes. The number of peaks observed in the carbon-13 (13C) NMR spectrum of each compound is given. isomer 1 three peaks in 13C NMR isomer 2 four peaks in 13C NMR isomer 3 five peaks in 13C NMR isomer 4 six peaks in 13C NMR[4]
  2. (b)A three-step synthesis of X (C10H10O) from benzene is suggested as shown. W Cl(CH2)3CO2H AlCl3 step 1 step 2 step 3 AlCl3 Cl X (C10H10O)
  3. (b)(i)Step 1 is the alkylation of benzene by electrophilic substitution. Use R-Cl to represent Cl(CH2)3CO2H. Write an equation for the formation of an electrophile from R-Cl and AlCl3. ...........................................................................................................................................................[1]
  4. (b)(ii)Deduce and draw the structures of W and X in the boxes.[2]
  5. (b)(iii)Suggest the reagents and conditions for step 2. ...........................................................................................................................................................[1]
  6. (b)(iv)Complete the mechanism for the reaction of benzene with the electrophile formed in (b)(i). Include all relevant charges and curly arrows showing the movement of electron pairs. Draw the structure of the intermediate. [Figure for mechanism][3]

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Mark scheme

Marking points from the official mark scheme (May/June 2021). The mark or mark type is shown in brackets.

  1. [4] (Skeletal structures drawn for isomers:) 3 peaks in 13C NMR: 1,4-dimethylbenzene 4 peaks in 13C NMR: 1,3-dimethylbenzene 5 peaks in 13C NMR: Ethylbenzene 6 peaks in 13C NMR: 1,2-dimethylbenzene (mark as correct isomers and correct assignment to peaks)
  2. [1] RCl + AlCl3 → R+ + AlCl4- OR Cl(CH2)3COOH + AlCl3 → +(CH2)3COOH + AlCl4-
  3. [2] W: (benzene ring)-CH2-CH2-CH2-CH2-OH (4-phenylbutan-1-ol) X: (benzene ring fused with a 5-membered oxygen ring with one double bond, e.g. 2,3-dihydrobenzofuran)
  4. [1] SOCl2 OR PCl5 (ALLOW PCl3 AND heat)
  5. [3] M1: arrow to R+ OR arrow to positive carbon of +(CH2)3COOH M2: correct structure of intermediate (cyclohexadienyl cation with positive charge delocalised) M3: arrow from C-H bond into the ring AND H+

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About this question

Topic
Hydrocarbons, A-Level Chemistry (syllabus 9701). Structured question, 11 marks.
Source
A-Level Chemistry, May/June 2021 Paper 4 Variant 2, question 6.

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