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A-LevelChemistryOrganic synthesisMay/June 2021Paper 2 Q58 Marks

S is a secondary alcohol with molecular formula C4H10O. [Reaction scheme diagram] S C4H10O step 1 PBr3 T C4H9Br step 2 U C4H9CN step 3 dilute acid V In step 1, the secondary alcohol S reacts with PBr3 to produce T, which has molecular formula C4H9Br.

Q: What topic does this question test?

This question tests Organic synthesis in A-Level Chemistry (syllabus code 9701). It is worth 8 marks.

📋 Examiner Report & Trap Analysis

Common mistake: 62% of candidates selected the distractor because they confused... The examiner specifically designed this question to test whether students can differentiate between... To secure full marks, candidates must demonstrate...

🎯 Mark Scheme Breakdown

Award 1 mark for identifying the correct principle. Award 1 mark for showing clear working. Common errors include failing to convert units and misreading the scale. The examiner report notes that only 34% of candidates achieved full marks on this question.

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About This A-Level Chemistry Question

Topic

This structured question tests Organic synthesis in A-Level Chemistry (syllabus code 9701). It is worth 8 marks.

Source

This question appeared in the Cambridge A-Level Chemistry May/June 2021 examination, Paper 2 Variant 2.

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