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A-LevelChemistryEquilibria9701/42 · May/June 2020 · Q19 Marks

EDTA⁴⁻, is a polydentate ligand.

  1. (a)(i)Explain what is meant by the term polydentate ligand.[2]
  2. (a)(ii)When a solution containing EDTA⁴⁻ is added to a solution containing [Cd(H₂O)₆]²⁺ a new complex is formed, [CdEDTA]²⁻. equilibrium 1 [Cd(H₂O)₆]²⁺ + EDTA⁴⁻ ⇌ [CdEDTA]²⁻ + 6H₂O Circle, on the structure of EDTA⁴⁻, the six atoms that form bonds with the metal ion. EDTA⁴⁻ -O-CCH₂ CH₂C-O- NCH₂CH₂N -O-CCH₂ CH₂C-O-[1]
  3. (a)(iii)Write an expression for the stability constant, Kstab1, for equilibrium 1, and state its units. Kstab1 = units =[2]
  4. (b)(i)Keq4 is the equilibrium constant for equilibrium 4. Write an expression for Keq4 in terms of Kstab2 and Kstab3. Keq4 =[1]
  5. (b)(ii)Calculate the value of the standard Gibbs free energy change, ∆G°, for equilibrium 4 at 298 K. ∆G° = kJ mol⁻¹ [2][2]
  6. (b)(iii)State how the value of ∆G° changes as the temperature increases. Explain your answer.[1]

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Mark scheme

Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.

  1. [2] M1 (a species) that donates/uses a many lone pairs/more than one lone pair M2 to form a dative/coordinate to a metal atom/metal ion/TM/TE/metal OR M1 (a species) that donates/uses lone pairs to form many/more than one M2 dative/coordinate bond to a metal atom/metal ion/TM/TE/metal
  2. [1] structure of EDTA any six atoms circled of 2 N & 4 O
  3. [2] M1 Kstab1 = [[CdEDTA]²⁻]/[[Cd(H₂O)₆]²⁺][EDTA⁴⁻] M2 units = mol⁻¹ dm³
  4. [1] Keq4 = Kstab3/Kstab2
  5. [2] M1 ΔG° = ΔH° - TΔS° ΔG° = 0.84 – (298*0.0809) M2 ΔG° = -23.3 (kJ mol⁻¹) 3sf min
  6. [1] more negative as TΔS increases OR more negative as ΔS is positive

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About this question

Topic
Equilibria, A-Level Chemistry (syllabus 9701). Structured question, 9 marks.
Source
A-Level Chemistry, May/June 2020 Paper 4 Variant 2, question 1.

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