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A-LevelChemistryCarboxylic acids and derivatives9701/41 · May/June 2020 · Q623 Marks

Compare and explain the relative acidities of 2-chloropropanoic acid, 3-chloropropanoic acid, and propanoic acid. Explain your answer. >........................................................... >........................................................... most acidic least acidic explanation

  1. (a)Compare and explain the relative acidities of 2-chloropropanoic acid, 3-chloropropanoic acid, and propanoic acid. Explain your answer. >........................................................... >........................................................... most acidic least acidic explanation[3]
  2. (b)(i)The numerical values of Ka for methanoic acid, HCO2H, and pyruvic acid, CH3COCO2H, are given. acid Ka HCO2H 1.78 x 10-4 CH3COCO2H 4.07 x 10-3 An equilibrium mixture containing the two acid-base pairs is formed. HCO2¯ + CH3COCO2H ⇌ HCO2H + CH3COCO2¯ Use the Ka values to calculate the equilibrium constant, Keq, for this equilibrium. Keq = [1]
  3. (b)(ii)Use your value of Keq to predict the position of this equilibrium. Indicate this by placing a tick (✔) in the appropriate box in the table. Explain your answer. equilibrium lies equilibrium lies equilibrium lies to the left in the middle to the right[1]
  4. (b)(iii)Ethanedioic acid, HO2CCO2H, has two dissociation constants, Ka1 and Ka2, whose pKa values are 1.23 and 4.19. Suggest equations to show the two dissociations that give rise to these pKa values. pKa1 1.23 pKa2 4.19[2]
  5. (b)(iv)State the mathematical relationship between pKa and the acid dissociation constant Ka.[1]
  6. (c)Three tests were carried out on separate samples of the organic acids shown in the table. The following results were obtained. ✓ = observed change X = no observed reaction [Table with test 1, 2, 3 rows and columns for reagent(s) and conditions, HCO2H, CH3COCO2H, HO2CCO2H, observed change. Some cells contain ✓ or X, others are blank.] Complete the table with the reagent(s) and conditions and the observed change for each test. Assume these organic acids all have a similar acid strength.[5]
  7. (d)A sample of pyruvic acid, CH3COCO2H, is analysed by carbon-13 NMR spectroscopy. Three peaks are observed. Complete the table by: • circling the carbon atom responsible for the chemical shift • stating the hybridisation of the circled carbon atom. [Table with chemical shift (δ) values 27, 163, 192 and blank columns for carbon atom responsible and hybridisation.][2]
  8. (e)An ester of pyruvic acid, F, is dissolved in CDCl3 and analysed by proton NMR spectroscopy. [Figure showing the structure of compound F, an ester of pyruvic acid: CH3-C(=O)-CO-OCH2CH3] The proton NMR spectrum of F is shown. [Figure showing the proton NMR spectrum of F with peaks at approximately 1.3, 2.2, 4.0 ppm] Use the proton NMR spectrum of F to complete the table. [Table with chemical shift (δ) values 1.3, 2.2, 4.0 and blank columns for group responsible, splitting pattern, and number of 1H atoms.][3]
  9. (f)Deuterium oxide, D2O, where D is 2H, can be used as a solvent in proton NMR spectroscopy. The proton NMR spectrum of alanine in CDCl3 has 4 peaks. The proton NMR spectrum of alanine in D2O has 2 peaks. alanine [Figure showing the structure of alanine: NH2-CH(CH3)-COOH] On the diagram of alanine, circle the protons that show peaks in both NMR spectra. Explain your answer.[2]
  10. (g)(i)The ionic product, Kw, for D2O has a value of 1.35 × 10-15 mol² dm–6 at 298 K. Write the expression for the Kw of D2O. Kw =[1]
  11. (g)(ii)Calculate the pH of pure, neutral D2O at 298 K. Assume [D+] is equivalent to [H+] for pH calculations. pH =[2]

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Mark scheme

Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.

  1. [3] M1 2-chloropropanoic acid > 3-chloropropanoic acid > propanoic acid [1]
  2. [3] M2 CH3CHCICO2H / CICH2CH2CO2H (are more acidic) as they contain an electronegative Cl atom so weaken O-H bond / stabilise carboxylate anion [1]
  3. [3] M3 CH3CHCICO2H (is more acidic than CICH2CH2CO2H) as the Cl atom is closer to CO2H so weaken O-H bond more / stabilise carboxylate anion more [1]
  4. [1] Keq = 4.07x10-3/1.78x10-4 = 22.9
  5. [1] 3rd box ticked [to the right] AND as the Keq is greater than one ecf on Keq
  6. [2] pKa 1.23 HO2CCO2H + H2O ⇌ HO2CCO2- + H3O+ OR HO2CCO2H ⇌ HO2CCO2- + H+
  7. [2] pKa 4.19 HO2CCO2- + H2O ⇌ -O2CCO2- + H3O+ OR HO2CCO2- ⇌ -O2CCO2- + H+
  8. [1] pKa = - logKa
  9. [5] M1 Tollen's reagent, warm OR Fehling's solution, warm silver mirror (brick)-red ppt.
  10. [5] M2 aqueous alkaline iodine OR 2,4-DNPH yellow ppt. orange ppt.
  11. [5] M3 acidified MnO4, warm decolourises (and bubbles)
  12. [2] chemical shift (δ) environment of the carbon atom hybridisation of the carbon atom 27 CH3 circled sp3 163 COOH circled sp2 192 C=O(COOH) circled sp2 Award one mark for each correct column
  13. [3] chemical shift (δ) group responsible for the peak splitting pattern number of 1H atoms responsible for the peak 1.3 alkane / CH / CH3 triplet 3 2.2 CH3CO or alkyl / CH next to C=O singlet 3 4.0 CH2O or alkyl / CH next to electronegative atom / C=O quartet / quadruplet 2 Award one mark for every three correct responses.
  14. [2] CH AND CH3 circled
  15. [2] these protons do not exchange with D2O OR OH and NH protons exchange with D2O
  16. [1] Kw = [D+][DO-]
  17. [2] M1 [D+] = √1.35 x 10-15 = 3.67 x10-8
  18. [2] M2 pH = -log [D+] = 7.4(3) min 2sf

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About this question

Topic
Carboxylic acids and derivatives, A-Level Chemistry (syllabus 9701). Structured question, 23 marks.
Source
A-Level Chemistry, May/June 2020 Paper 4 Variant 1, question 6.

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