When an organic acid, RCOOH, is neutralised by an alkali an exothermic reaction takes place. You will determine the enthalpy change of neutralisation, ΔH, for the following reaction. RCOOH(aq) + NaOH(aq) → RCOONa(aq) + H₂O(l) In this equation R is an alkyl group. FA 3 is a solution containing 120.1 g dm⁻³ of RCOOH. FA 4 is aqueous sodium hydroxide, NaOH.
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