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A-LevelChemistryHalogen derivatives9701/41 · May/June 2019 · Q915 Marks

Organochlorine compounds can undergo hydrolysis. R-Cl + H₂O → R−OH + HCl

  1. (a)State and explain the relative rates of hydrolysis of the following compounds. CH3CH2Cl CH3COCl C6H5Cl[3]
  2. (b)(i)Epibatidine is a naturally occurring organochlorine compound. [Figure 9.b] State what is meant by the term weak base.[1]
  3. (b)(ii)A molecule of epibatidine contains two nitrogen atoms, both of which can act as a base. Epibatidine reacts with HCl(aq). Complete the structure to suggest the product formed in this reaction. [Figure 9.b.ii][1]
  4. (c)(i)Polyamides, such as nylon-6, can be prepared from a monomer that contains both an amine and an acyl chloride functional group. [Figure 9.c] When the nylon-6 monomer is hydrolysed, bonds are broken and formed. By considering the two steps in the mechanism of the reaction, complete the table by placing one tick (✔) in each row to indicate the types of bonds broken and formed during the mechanism. [Table 9.c.i: bonds broken | σ bonds only | π bonds only | both σ and π bonds bonds formed | σ bonds only | π bonds only | both σ and π bonds][1]
  5. (c)(ii)Draw two repeat units of nylon-6. The amide bond should be shown fully displayed.[2]
  6. (d)An addition polymer made from two different alkene monomers is called a co-polymer. A section of a polyalkene co-polymer is shown. [Figure 9.d] Draw the structure of the two alkene monomers which produce this co-polymer.[2]
  7. (e)Explain why polyamides normally biodegrade more readily than polyalkenes.[1]
  8. (f)(i)The alkene phenylethene can be prepared from benzene in three steps. [Figure 9.f] Deduce the identity of compound H and draw its structure in the box.[1]
  9. (f)(ii)Suggest reagents and conditions for each of the steps 1–3. step 1 step 2 step 3[3]

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Mark scheme

Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.

  1. M1: CH3COCl > CH3CH2Cl > C6H5Cl
  2. M2 & M3 any two from: • in C6H5Cl (no hydrolysis) C-Cl bond is part of delocalised system OR p-orbital on Cl overlaps with π system OR electrons from Cl overlap with π system • CH3COCl carbon in C-Cl bond is more electron deficient since it is also attached to an oxygen atom (ora) or C-Cl bond strength is weakest in CH3COCl (ora) • CH3CH2Cl carbon in C-Cl bond strengthened by positive inductive effect of alkyl group
  3. partially ionised and proton acceptor
  4. CI H. + N H N ct or CI H. + N N H
  5. bonds broken: both σ- and π-bonds (tick) / bonds formed: σ-bonds only (tick) Both ticks correct
  6. -N-(CH2)5——————C————N─(CH2)5-C- H H M1: amide link M2: rest of the structure
  7. CH3CCl=CH2 and C2H5CH=CHCH3 each correct structure scores one mark
  8. C-C bonds are non-polar / polyalkenes cannot be hydrolysed and polyamides can be broken down by hydrolysis
  9. OH (structure showing ethylbenzene with an -OH group)
  10. M1: step 1: CH3COCl + AlCl3 [1]
  11. M2: step 2: NaBH4 / LiAlH4 [1]
  12. M3: step 3: conc. H2SO4, heat [1]

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About this question

Topic
Halogen derivatives, A-Level Chemistry (syllabus 9701). Structured question, 15 marks.
Source
A-Level Chemistry, May/June 2019 Paper 4 Variant 1, question 9.

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