A group of ecologists investigated the biodiversity of two peat bog ecosystems, A and B. Peat bogs are wetland ecosystems that often contain rare species. Fig. 2.1 shows an example of a peat bog. [Figure 2.1]
- (a)The ecologists sampled the plant species in peat bog A and peat bog B. The ecologists decided to use two suitable indices of biodiversity: • Simpson's index of diversity • Shannon diversity index. The ecologists had read that the two indices can lead to different conclusions. The Shannon diversity index gives values in the range 1.5–3.5, where 1.5 is low biodiversity and 3.5 is high biodiversity. The results are shown in Table 2.1. [Table 2.1] The ecologists concluded that one index indicated peat bog A had more biodiversity, but the other index indicated peat bog B had more biodiversity. Suggest how the differences in the data in the two samples, shown in Table 2.1, may have led to the different conclusions. [2][2]
- (b)The ecologists sampled the invertebrate species in peat bogs A and B and calculated invertebrate biodiversity using Simpson's index of diversity.
- (b)(i)The ecologists sampled invertebrate species in peat bog A: • between 13:00 and 16:00 on three different days within a 30-day period • at 10 random sites along the edge of a path in the peat bog • by sampling the invertebrates within a 1 m² quadrat placed at each site • by using an identification key to identify the species • by counting the number of individuals of each species. Describe how this sampling method could be improved to make sure the results are more representative of all invertebrates in the whole of peat bog A. [3][3]
- (b)(ii)Table 2.2 shows the results of the invertebrate sampling in peat bog A. The formula for Simpson's index of diversity (D) is: D = 1 - Σ(n/N)² n = number of individuals of each species present in the sample N = total number of all individuals of all species present in the sample Complete Table 2.2 and use the formula provided to calculate Simpson's index of diversity. [Table 2.2] Simpson's index of diversity (D) = ..................................................... [3][3]
- (b)(iii)The ecologists calculated a D value of 0.710 for peat bog B. Use your value of D from (b)(ii) to compare the biodiversity of peat bog A and peat bog B. [1][1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [1] (a) peat bog A has a higher number of species and a higher Shannon index (than peat bog B); ora
- [1] (a) peat bog B has a smaller range of species abundance and a higher Simpson's index (than peat bog A) ; ora
- [1] (a) if mp1 and mp2 not awarded, then award 1 mark for: peat bog A has a higher number of species and peat bog B has a smaller range of species abundance ; ora
- [1] (b)(i) sample at different times of the year (not only over one month) ;
- [1] (b)(i) sample at, night / different times of day (not only between 13:00 and 16:00) ;
- [1] (b)(i) sample at sites other than along the path ;
- [1] (b)(i) use of (another) named technique to sample invertebrates ;
- [1] (b)(i) use an expert / (identification) app / guidebook (instead of an identification key);
- [1] (b)(ii) (for Tipula limbata) n / N = 0.083 and (n / N)² = 0.007 ;
- [1] (b)(ii) Σ = 0.270 ;
- [1] (b)(ii) D = 0.730;
- [1] (b)(iii) peat bog A has (slightly) higher (biodiversity than peat bog B); ora
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →