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A-LevelBiologyEnzymes9700/22 · Feb/Mar 2018 · Q311 Marks

The unicellular fungus Kluyveromyces lactis is found in dairy products. It is a safe microorganism to culture for the extraction of the enzyme lactase. Lactase catalyses the breakdown of lactose, a sugar found in milk. The reaction catalysed by lactase is summarised in Fig. 3.1. [Figure 3.1]

  1. (a)Describe the reaction that is catalysed by lactase. Use Fig. 3.1 to help you. In your answer, identify R and product S.[4]
  2. (b)(i)On a commercial scale, immobilised lactase can be used to produce lactose-free milk. One of the products of the reaction shown in Fig. 3.1 acts as an inhibitor of lactase. This is an example of product inhibition. Suggest why product inhibition is useful in K. lactis when lactase is acting as an intracellular enzyme, but can be a disadvantage when extracted lactase is used free in solution for the production of lactose-free milk.[2]
  3. (b)(ii)Suggest how using immobilised lactase in a commercial application helps to reduce the problem of product inhibition.[1]
  4. (b)(iii)The first large-scale production of lactose-free milk with an immobilised enzyme used lactase trapped in cellulose triacetate fibres. Suggest one feature of cellulose triacetate that makes it useful as an immobilising material.[1]
  5. (c)For a commercial application using an enzyme, the progress of the enzyme-catalysed reaction needs to be studied. Outline how the progress of an enzyme-catalysed reaction can be investigated experimentally.[3]

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Mark scheme

Marking points from the official mark scheme (Feb/Mar 2018). The mark or mark type is shown in brackets.

  1. [4] any four from: 1 disaccharide to monosaccharides ; 2 R is water / water required; 3 hydrolysis reaction ; 4 glycosidic bond broken ; 5 S is a-glucose ; 6 detail of enzyme action; e.g. induced fit or lock and key hypothesis described 7 AVP; e.g. (β-)1,4(-glycosidic) broken
  2. [2] intracellular advantage: idea of control / maintaining balance / efficient metabolism ; e.g. if, (enough) glucose / galactose / monosaccharides, present then no need for, uptake / breakdown, of lactose avoids osmotic problems as no build-up of monosaccharides high quantities of product means no requirement for use in respiration by cell disadvantage: loss of product / reduced productivity / product required continuously / slows rate of reaction / ref. to enzyme needing to remain active ;
  3. [1] any one from: products and enzyme kept separated / AW ; product removed immediately;
  4. [1] any one from: inert / unreactive / cannot be digested by lactase / AW; non-toxic; insoluble; long shelf-life; AVP; e.g. can create small mesh size suggestion of enzyme attachment to fibres
  5. [3] any three from: 1 ref. to controlled variables; e.g. constant, pH / temperature 2 take samples at timed intervals; A regular intervals 3 determine, substrate concentration / product concentration; 4 plot graph of, dependent variable (y-axis) against time (x-axis); 5 ref. to rate of disappearance of substrate or ref. to rate of appearance of product ; 6 determine initial rate;

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About this question

Topic
Enzymes, A-Level Biology (syllabus 9700). Structured question, 11 marks.
Source
A-Level Biology, Feb/Mar 2018 Paper 2 Variant 2, question 3.

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