O-LevelAdditional MathematicsEquations, inequalities and graphs4037/12 · Oct/Nov 2018 · Q36 Marks
On the axes below, sketch the graph of y = |6-3x|, showing the coordinates of the points where the graph meets the coordinate axes.
- (i)On the axes below, sketch the graph of y = |6-3x|, showing the coordinates of the points where the graph meets the coordinate axes.[2]
- (ii)Solve |6-3x| = 2.[3]
- (iii)Hence find the values of x for which |6-3x|> 2.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.
- [B2] B1 for correct shape with vertex at (2,0)
- [Dep B1] for passing through or starting at (0,6)
- [B1] For x = 4/3
- [M1] For considering – 2
- [A1]
- Or [M1] For squaring each side and attempt to solve a 3 term quadratic = 0
- [A1]
- [A1]
- [B1] FT on their solutions in part (ii), must both be positive and written as 2 separate statements
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