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O-LevelAdditional MathematicsTrigonometry4037/12 · Oct/Nov 2018 · Q14 Marks

Solve 1 + √2 sin(x+50°) = 0 for -180° ≤ x ≤ 180°.

  1. (a)Solve 1 + √2 sin(x+50°) = 0 for -180° ≤ x ≤ 180°.[4]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.

  1. [M1] For order of operations – subtraction of 1, division by ±√2 and attempt at sin⁻¹
  2. [M1] Dep For obtaining a solution by subtracting 50°
  3. [A2] A1 for one correct solution
  4. [A1] Al for a second correct solution and no others within the range

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About this question

Topic
Trigonometry, O-Level Additional Mathematics (syllabus 4037). Structured question, 4 marks.
Source
O-Level Additional Mathematics, Oct/Nov 2018 Paper 1 Variant 2, question 1.

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