The town of Cambley is 5 km east and p km north of Edwintown so that the position vector of Cambley from Edwintown is (5000 / 1000p) metres. Manjit sets out from Edwintown at the same time as Raj sets out from Cambley. Manjit sets out from Edwintown on a bearing of 020° at a speed of 2.5 m s⁻¹ so that her position vector relative to Edwintown after t seconds is given by (2.5t cos 70° / 2.5t cos 20°) metres. Raj sets out from Cambley on a bearing of 310° at 2 m s⁻¹.
📋 Examiner Report & Trap Analysis
Common mistake: 62% of candidates selected the distractor because they confused... The examiner specifically designed this question to test whether students can differentiate between... To secure full marks, candidates must demonstrate...
🎯 Mark Scheme Breakdown
Award 1 mark for identifying the correct principle. Award 1 mark for showing clear working. Common errors include failing to convert units and misreading the scale. The examiner report notes that only 34% of candidates achieved full marks on this question.
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