The diagram shows two circles, centres A and B, each of radius 10cm. The point B lies on the circumference of the circle with centre A. The two circles intersect at the points C and D. The point E lies on the circumference of the circle centre B such that ABE is a diameter. [Figure 10.1]
- (i)Explain why triangle ABC is equilateral.[1]
- (ii)Write down, in terms of π, angle CBE.[1]
- (iii)Find the perimeter of the shaded region.[5]
- (iv)Find the area of the shaded region.[3]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2015). The mark or mark type is shown in brackets.
- [B1] for a convincing argument
- [B1] Angle CBE = 2π/3 (must be in terms of π, allow 0.667π, or better)
- [M1] for correct attempt to find DE using their angle CBE
- [A1] for correct DE, allow 17.3 or better
- [M1] for attempt to find arc length with their angle CBE (20.94)
- [M1] for 10 + 10 + DE + an arc length
- [A1] allow unsimplified
- [M1] for sector area using their angle CBE allow unsimplified, may be implied
- [M1] for triangle area using their angle DBE which must be the same as their angle CBE, allow unsimplified, may be implied
- [A1] allow in either form
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