Variables x and y are such that y = (x - 3)ln(2x² + 1).
- (i)Find the value of dy/dx when x = 2.[4]
- (ii)Hence find the approximate change in y when x changes from 2 to 2.03.[2]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2015). The mark or mark type is shown in brackets.
- [B1] for correct differentiation of ln function
- [M1] for attempt to differentiate a product
- [A1] for correct product, terms must be bracketed where appropriate
- [A1] for correct final answer
- [M1] for attempt to use small changes
- [A1FT] follow through on their numerical answer to (i) allow to 2 sf or better
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