The diagram shows part of the curve y = e^(x/3). The tangent to the curve at P (9, e³) meets the x-axis at Q. [Figure showing a curve y=e^(x/3) and a tangent at P(9, e³) meeting x-axis at Q, shaded region between curve, axes and tangent]
- (i)Find the coordinates of Q.[4]
- (ii)Find the area of the shaded region bounded by the curve, the coordinate axes and the tangent to the curve at P.[6]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2013). The mark or mark type is shown in brackets.
- [B1] dy/dx = 1/3 e^(x/3)
- [M1] m = 1/3 e³ For insertion of x = 9 into their dy/dx. 6.7 or better if correct.
- [DM1] y-e³ = 1/3 e³ (x – 9) Using their evaluated m to find eqn y = 6.7x-40.2 or better if correct.
- [A1] At Q y = 0, x = 6 Accept value that rounds to 6.0 to 2sf
- [B1] Area triangle 1.5e³ or 30.1
- [B1] ∫e^(x/3) dx = 3e^(x/3) oe
- [M1] Uses limits of 0 and 9 in integrated function. + must see both values inserted if incorrect answer
- [A1] 3e³ - 3 or 57.3
- [M1] Area under curve subtract area of triangle
- [A1] 1.5e³ - 3 or 27.1 Condone 27.2 if obtained from 57.3 - 30.1.
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