Find ∫(9 + sin 3x)dx.
- (i)Find ∫(9 + sin 3x)dx.[3]
- (ii)Hence show that ∫(from π/9 to π/3) (9 + sin 3x) dx = aπ + b, where a and b are constants to be found.[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2013). The mark or mark type is shown in brackets.
- [B1] (i) 9x
- [B1] -1/3 cos 3x
- [B1] Condone omission of + c
- [M1] (ii) for correct use of limits in their answer to (i)
- [A1] for each term (e.g. 3π + 1/3 and π - 1/6)
- [A1] for final answer (2π + 1/2)
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