Answer only one of the following two alternatives. EITHER A curve is such that y = 5x² / (1 + x²)
- (EITHER)(i)Show that dy/dx = kx / (1 + x²)², where k is an integer to be found.[4]
- (EITHER)(ii)Find the coordinates of the stationary point on the curve and determine the nature of this stationary point.[3]
- (EITHER)(iii)By using your result from part (i), find ∫ x / (1 + x²)² dx and hence evaluate ∫₂³ x / (1 + x²)² dx.[4]
- (OR)A curve is such that y = (Ax² + B) / (x² - 2) , where A and B are constants.
- (OR)(i)Show that dy/dx = 2x(2A + B) / (x² - 2)².[4]
- (OR)(ii)It is given that y = -3 and dy/dx = -10 when x = 1. Find the value of A and of B.[3]
- (OR)(iii)Using your values of A and B, find the coordinates of the stationary point on the curve, and determine the nature of this stationary point.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2012). The mark or mark type is shown in brackets.
- [M1] M1 for attempt to differentiate a quotient -1 each error
- [A2,1,0]
- [A1]
- [B1] Stationary point at (0, 0)
- [M1] M1 for a correct attempt to determine the nature of the turning point (allow change of sign method) – just finding the second derivative is not enough.
- [A1] When x = 0, d²y/dx² is +ve, minimum
- [B1] B1 for ∫ x/(1+x²)² dx = -1/(2(1+x²)) (+c)
- [B1] B1 for limits
- [M1] M1 for correct use of limits in an attempt at integration
- [A1]
- [M1] M1 for attempt to differentiate a quotient -1 each error
- [A2,1,0]
- [A1] Answer given
- [M1] M1 for use of conditions once
- [M1] M1 for use of conditions a second time and attempt to solve resulting equations
- [A1]
- [B1] B1 for correct x
- [B1] B1 for y = -B/2
- [M1] M1 for a correct attempt to determine the nature of the turning point (allow change of sign method) – just finding the second derivative is not enough.
- [A1] A1 for a correct conclusion from completely correct work.
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