Answer only one of the following two alternatives. EITHER The diagram shows an isosceles triangle AOB and a sector OCDEO of a circle with centre O. The line AB is a tangent to the circle. Angle AOB = 1.8 radians and the radius of the circle is 12 cm. OR The diagram shows part of the curve y=xsinx and the normal to the curve at the point P(π/2, π/2). The curve passes through the point Q(π, 0).
- (EITHER)(i)Show that the distance AC = 7.3 cm to 1 decimal place.[2]
- (EITHER)(ii)Find the perimeter of the shaded region.[6]
- (EITHER)(iii)Find the area of the shaded region.[4]
- (OR)(i)Show that the normal to the curve at P passes through the point Q.[4]
- (OR)(ii)Given that (d/dx)(xcosx) = cosx – xsinx, find ∫xsinxdx.[3]
- (OR)(iii)Find the area of the shaded region.[5]
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Mark scheme
Marking points from the official mark scheme (May/June 2011). The mark or mark type is shown in brackets.
- [1] (EITHER)(i) OA = 12/cos0.9
- [1] (EITHER)(i) AC = 19.3 - 12 = 7.3
- [1] (EITHER)(ii) Complete method for major arc (2π− 1.8) × 12
- [1] (EITHER)(ii) 53.8
- [1] (EITHER)(ii) AB = 2 × 12tan0.9 or cosine rule
- [1] (EITHER)(ii) 30.2
- [1] (EITHER)(ii) Complete plan (53.8 + 30.2 + 2 × 7.3)
- [1] (EITHER)(ii) 98.6
- [1] (EITHER)(iii) Complete method for major sector (1/2) × 12² × (2π−1.8)
- [1] (EITHER)(iii) (1/2) × 19.3² × sin1.8 or (1/2) × 30.2 × 12
- [1] (EITHER)(iii) 323 or 181
- [1] (EITHER)(iii) 504
- [1] (OR)(i) Uses product rule dy/dx = sinx + x cos x
- [1] (OR)(i) At x = π/2 gradient = 1
- [1] (OR)(i) Uses m₁m₂ = -1
- [1] (OR)(i) Correctly reaches conclusion. e.g. y - π/2 = -1 (x - π/2) with y = 0
- [1] (OR)(ii) ∫cosx dx – ∫x sinx dx = x cos x
- [1] (OR)(ii) ∫x sinx dx = ∫cos x dx - x cos x
- [1] (OR)(ii) sinx - xcosx
- [1] (OR)(iii) Uses limits of π and π/2
- [1] (OR)(iii) 2.14 or π – 1
- [1] (OR)(iii) Area triangle = (1/2) × (π/2) × (π/2) = π²/8 or 1.23
- [1] (OR)(iii) Subtracts area of triangle
- [1] (OR)(iii) 0.908 (allow 0.906 or 0.907) or 0.91 or π - 1 - π²/8
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