OR A particle moves in a straight line so that, at time t s after passing a fixed point O, its velocity is v m s⁻¹, where v = 6t + 4 cos 2t. Find
- (i)the velocity of the particle at the instant it passes O,[1]
- (ii)the acceleration of the particle when t = 5,[4]
- (iii)the greatest value of the acceleration,[1]
- (iv)the distance travelled in the fifth second.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2010). The mark or mark type is shown in brackets.
- [B1] (i) 4
- [M1] (ii) Differentiate v to find an expression for a
- [A1] (ii) 6 – 8 sin 2t
- [DM1] (ii) Substitute t=5
- [A1] (ii) 10.3 to 10.4
- [B1] (iii) 14
- [M1] (iv) Integrate v to find an expression for s
- [A1] (iv) s = 3t² + 2 sin 2t
- [DM1] (iv) Use limits 4 and 5
- [A1] (iv) 23.9
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