In this question, all lengths are in centimetres and all angles are in radians. [Figure showing a sector AOB of a circle and a cone formed from it] The diagram shows a sector AOB of a circle, centre O, radius 15. Angle AOB = 6π/5. The sector is made into a cone with points A and B touching, as shown.
- (a)Find the curved surface area of the cone.[2]
- (b)The top of the cone is a horizontal circle. Find the circumference of the circular top.[2]
- (c)Hence find the radius of the circular top and the perpendicular height of the cone.[2]
- (d)(i)When the depth of the water in the cone is h, the radius of the circular top of the water is r. Find an expression for r in terms of h.[1]
- (d)(ii)The water is poured into the cone at a constant rate of 27 cm³ per second. Find the rate at which the depth of the water is rising when the depth of the water is 4.[5]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2025). The mark or mark type is shown in brackets.
- [M1] for 1/2 x 15² x 6π/5 oe
- [A1] 135π isw or 424 or 424.1 to 424.2
- [M1] for 15 x 6π/5 oe
- [A1] 18π or 56.5 to 56.6
- [B1] for radius = 9 OR
- [M1] for a correct Pythagoras' statement e.g. their r² + height² = 15²
- [B1] radius = 9, height = 12
- [B1] r = 3/4 h oe
- [B1] FT their r = kh where k is a positive constant e.g. V = 1/3 π (their kh)² x h
- [B1] FT their k where k is a positive constant e.g. dV/dh = (theirk)² π x h²
- [B1] Relevant, correct chain rule including dh/dt soi e.g. dh/dt = dV/dt ÷ dV/dh
- [M1] 27 x 16 / (9π x 16) oe
- [A1] 0.955 or 0.9549[29...]
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