A geometric progression has a 4th term of 8k⁶/27 and a 6th term of 32k¹⁰/243, where k is a constant. The common ratio of this geometric progression is positive.
- (a)Find the common ratio in terms of k and the value of the first term of this geometric progression.[4]
- (b)Given that this geometric progression has a sum to infinity of 3, find the possible values of k.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2025). The mark or mark type is shown in brackets.
- [B1] ar³ = 8k⁶/27, ar⁵ = 32k¹⁰/243 soi (May be implied by a correct 5th term 16k⁸/81)
- [M1] Divide ar⁵ by ar³ to find r² (for solution of their equations to obtain either r=mk² or a=c, where m is an unsimplified numeric constant and c is a non-zero constant, e.g. Use of r² = 6th term / 4th term)
- [A1] r = 2k²/3
- [A1] a=1
- [B1] 1 / (1 - 2k²/3) = 3 soi (For use of sum to infinity formula with their values of a where a is numeric and r which is in terms of k²)
- [B1] k = ±1 (B1 for each must be from correct work)
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