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O-LevelAdditional MathematicsQuadratic functions4037/21 · May/June 2024 · Q33 Marks

Use algebra to show that the equation 5x(x-3) = 5x-26 has no real solutions.

  1. Use algebra to show that the equation 5x(x-3) = 5x-26 has no real solutions.[3]

Mark scheme

Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.

  1. [M1] 5x² – 20x + 26 [= 0]
  2. [M1] Correctly finds b² – 4ac for their 5x² – 20x + 26 [= 0] e.g. (–20)² – 4(5)(26)
  3. [A1] 400 – 520 < 0 or –120
  4. [(M1)] Condone one slip in expansion of brackets or collection of terms (5x² – 20x + 26 [= 0])
  5. [(M1)] Completes the square 5(x – 2)² + 6 and states the correct minimum point (2, 6)
  6. [(A1)] Correct conclusion e.g. Minimum point at y = 6 therefore does not intersect x-axis oe

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About this question

Topic
Quadratic functions, O-Level Additional Mathematics (syllabus 4037). Structured question, 3 marks.
Source
O-Level Additional Mathematics, May/June 2024 Paper 2 Variant 1, question 3.

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