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O-LevelAdditional MathematicsLogarithmic and exponential functions4037/11 · May/June 2024 · Q39 Marks

3 (a) Write 1+1g(x² - 1) - 21g(x-1), where x > 1, as a single logarithm to base 10. Give your answer in its simplest form. (b) Solve the equation 4 log5(x+1) = 9log(x+1) 5, giving your answers in the form a+b√c, where a, b and c are constants.

  1. (a)Write 1+1g(x² - 1) - 21g(x-1), where x > 1, as a single logarithm to base 10. Give your answer in its simplest form.[4]
  2. (b)Solve the equation 4 log5(x+1) = 9log(x+1) 5, giving your answers in the form a+b√c, where a, b and c are constants.[5]

Mark scheme

Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.

  1. [4] B1 (for 3a) 1=lg10 soi
  2. [4] M1 For correct use of logs power rule or multiplication or division rule. i.e.: Award M1 for example: 2log(x-1) = log(x – 1)² or log(x² - 1) = log(x - 1) + log(x + 1) or log10 + log(x² - 1) = log10(x² -1) or log(x² - 1) - log(x – 1)² = log (x²-1)/(x-1)²
  3. [4] DM1 Dep on previous M1 for a correct attempt to factorise and an attempt to simplify
  4. [4] A1 (lg(10(x+1))/(x-1))
  5. [5] B1 For change of base
  6. [5] M1 for a correct method in forming a quadratic equation Dep on previous B1
  7. [5] M1 Dep on dealing with logarithms correctly Allow if ± is missing
  8. [5] A1 x=-1+5√5, −1-√5/4

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About this question

Topic
Logarithmic and exponential functions, O-Level Additional Mathematics (syllabus 4037). Structured question, 9 marks.
Source
O-Level Additional Mathematics, May/June 2024 Paper 1 Variant 1, question 3.

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