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O-LevelAdditional MathematicsLogarithmic and exponential functions4037/22 · May/June 2023 · Q59 Marks

Variables P and T are known to be connected by the relationship P = Abᵀ, where A and b are constants. Values of P are found for certain values of time, T.

  1. (a)Show that a graph of lg P against T will be a straight line.[2]
  2. (b)The diagram shows the graph of lg P against T. The graph passes through (0, 6) and (14, 12). Find the values of A and b.[4]
  3. (c)Using the graph or otherwise, find the length of time for which P is between 100 million and 1000 million.[3]

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Mark scheme

Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.

  1. [B2] lg P = lg A + T lg b oe nfww Must be seen and not from wrong working
  2. [B1] for lg P = lg A + T lg b isw, nfww
  3. [B1] and correct comparison with y = mx + c soi
  4. [B2] A = 10⁶ oe isw and b = 10^(3/7) oe isw
  5. [B2] for A = 10⁶ oe isw
  6. [B1] correct method which could be used to find A e.g. lgA = 6 or 12 = (3/7)×14 + lg A
  7. [B2] for b = 10^(3/7) oe isw
  8. [B1] correct method which could be used to find b e.g. lgb = (12-6)/(14-0) oe or 12 = 14lgb+6
  9. [M1] lg P₁ = 8 and lg P₂ = 9 soi
  10. [M1] leading to T₁ = 4.6 to 4.8 or T₂ = 6.8 to 7.2
  11. [M1] If graph not used then allow M1 for substitution of their A and their b in the exponential equation as far as 10⁸/theirA = (theirb)^T and 10⁹/theirA = (theirb)^T OR substitution of their A and their b or their lgA and their lg b in the log equation lg10⁸ = their lg A + T(their lgb) or better and lg10⁹ = their lg A + T(their lgb) or better
  12. [A1] Difference of correct times: T₂-T₁ where T₂ = 6.8 to 7.2 T₁ = 4.6 to 4.8 Answer in range 2.2 to 2.4 nfww
  13. [M2] M1 for lg10⁸ = 8 and lg10⁹ = 9 and Change in lg P / Change in T = 3/7
  14. [A1] Answer in range 2.2 to 2.4 nfww

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About this question

Topic
Logarithmic and exponential functions, O-Level Additional Mathematics (syllabus 4037). Structured question, 9 marks.
Source
O-Level Additional Mathematics, May/June 2023 Paper 2 Variant 2, question 5.

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