Skip to main content
O-LevelAdditional MathematicsLogarithmic and exponential functions4037/12 · May/June 2023 · Q510 Marks

Find the exact solutions of the equation 6p^(1/3) - 5p^(-1/3) - 13 = 0.

  1. (a)Find the exact solutions of the equation 6p^(1/3) - 5p^(-1/3) - 13 = 0.[4]
  2. (b)Solve the equation 2lg(2x+5) - lg(x+2) = 1, giving your answers in exact form.[6]

Mark scheme

Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.

  1. [B1] May introduce their own variable e.g. x (6p^(2/3) - 13p^(1/3) - 5 = 0) soi
  2. [M1] For attempt to solve quadratic equation to obtain p^(1/3) = .. or e.g. x = ...
  3. [A1] Must be simplified and exact (p^(1/3) = 5/2 or p^(1/3) = -1/3)
  4. [A1] Must be simplified and exact (p = 125/8 or p = -1/27)
  5. [B1] lg(2x+5)²
  6. [B1] Dep on first B1, must be a correct statement lg((2x+5)² / (x+2))
  7. [B1] 1 = lg10 soi
  8. [M1] Dep on second B mark For correct attempt to obtain a quadratic equation with no log terms, where k = 1 or 10 (2x+5)² / (x+2) = k oe
  9. [M1] for attempt to solve their quadratic to obtain x = ..., implied by decimals of -1.8 or -0.69 or better
  10. [A1] for both, A0 if one is discarded (-5 ± √5) / 4 or exact equivalent

Write your answer and get it marked

On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.

Sign up free →

About this question

Topic
Logarithmic and exponential functions, O-Level Additional Mathematics (syllabus 4037). Structured question, 10 marks.
Source
O-Level Additional Mathematics, May/June 2023 Paper 1 Variant 2, question 5.

Questions and mark schemes are from past examination papers and remain the copyright of the exam board. How Oracle Prep builds its content

Related Additional Mathematics questions

© 2026 Oracle Prep