Given that y = (x²-1)√5x+2, show that dy/dx = (Ax²+Bx+C) / (2√5x+2) where A, B and C are integers.
- (a)Given that y = (x²-1)√5x+2, show that dy/dx = (Ax²+Bx+C) / (2√5x+2) where A, B and C are integers.[5]
- (b)Find the coordinates of the stationary point of the curve y = (x²-1)√5x+2, for x > 0. Give each coordinate correct to 2 significant figures.[3]
- (c)Determine the nature of this stationary point.[2]
Mark scheme
Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.
- [1] For (5/2)(5x+2)^(1/2)
- [1] For differentiation of a product
- [1]
- [1] Dep on previous M mark for attempt to simplify
- [1] dy/dx = (25x²+8x-5) / (2√5x+2)
- [1] Equating their numerator in (a) to zero and attempt to solve
- [1] x = 0.315
- [1] y = -1.70
- [1] Consideration of gradient or y values either side of stationary point, remembering that x > 0. Must be a complete method making use of their (a). Allow consideration of 25x² + 8x – 5 as a ‘minimum curve’. Accept 2nd derivative method.
- [1] Minimum
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