O-LevelAdditional MathematicsDifferentiation and integration4037/11 · May/June 2020 · Q56 Marks
Find the equation of the tangent to the curve y = ln(3x²-1) / (x+2) at the point where x = 1. Give your answer in the form y = mx+c, where m and c are constants correct to 3 decimal places.
- (a)Find the equation of the tangent to the curve y = ln(3x²-1) / (x+2) at the point where x = 1. Give your answer in the form y = mx+c, where m and c are constants correct to 3 decimal places.[6]
Mark scheme
Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.
- [B1] B1 for 6x/(3x^2-1)
- [M1] For attempt to differentiate a quotient or an equivalent product, must have correct order of terms and correct sign
- [A1]
- [B1] When x=1, y = -ln(2)/3 or 0.231(0)
- [B1] When x=1, dy/dx = 0.92298, allow 0.923
- [B1] y = 0.923x-0.692
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